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anonymous
 one year ago
would
\[LT \left[ tu(t30) \right]=\frac{ e ^{30s} }{ s ^{2} }\]
i'm not sure if applying the formula below would be right.
\[LT \left[ u _{c}(t)f(tc) \right]=e ^{cs}F(s)\]
anonymous
 one year ago
would \[LT \left[ tu(t30) \right]=\frac{ e ^{30s} }{ s ^{2} }\] i'm not sure if applying the formula below would be right. \[LT \left[ u _{c}(t)f(tc) \right]=e ^{cs}F(s)\]

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0we know that \[LT \left[ u _{c}(t)=u(tc) \right]=\frac{ e ^{cs} }{ s }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0just from laplace tables

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Have you tried going through the integration?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im unsure how to do that when we are considering u(t30)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do you know how to work with the dirac delta function?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0not really, we just have a table of lapalce transforms used to help us in process control. my laplace transform is limited considering we weren't taught this in engineering maths yet it has come up in a third year topic which applies laplace transforms

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0like, i start with the integral definition, \[LT(f(t)=\int\limits_{0}^{\infty}e ^{st}tu(t30)dt\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and try integration by parts...but i'm stuck with the t*u(t30) bit, with applying the product rule on it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok, so if you are using integration by parts, then you are considering this integral of the from\[\int\limits_{}^{}u dv = uv  \int\limits_{}^{}v du\]. What are you using as your u and your dv?

dan815
 one year ago
Best ResponseYou've already chosen the best response.3do a change of variables

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dv is the exponential and u is the t*u(t30)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah nah that drawing has confused me lel

dan815
 one year ago
Best ResponseYou've already chosen the best response.3i realized using s for the different variable was bad idea lol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0haha no joke i was gonna say

dan815
 one year ago
Best ResponseYou've already chosen the best response.3now u became the variable for laplace

dan815
 one year ago
Best ResponseYou've already chosen the best response.3lemme think so i wonder if we gotta add some extra stuff in for this shift

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0could we just expand those brackets

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so instead of s lets use 'a' as our variable

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(a+30)u(a)= au(a)+30u(a)

dan815
 one year ago
Best ResponseYou've already chosen the best response.3its best to jst graph this stuff so we know for sure we dont have anything funky going on

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and laplacing these would be the same...

dan815
 one year ago
Best ResponseYou've already chosen the best response.3ohh something silly here oops

dan815
 one year ago
Best ResponseYou've already chosen the best response.3ont need to even worry about all this apprently

dan815
 one year ago
Best ResponseYou've already chosen the best response.3this is U_c(t) by definition

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but we can't use the formula thats on the top page cause it involves f(tc) so here c=0 for the function f, but 30 for variable 'u'

dan815
 one year ago
Best ResponseYou've already chosen the best response.3i think what we did might be find, think abouut it like this, what is the laplace of this bottom graph

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0just a ramp function, shifted from the origin..

dan815
 one year ago
Best ResponseYou've already chosen the best response.3with this trick now we have a new function f(t)=t+30 and f(tc)=f(t30)=(t30)+30

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0with the first and second step dw:1443327215719:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0should the first step be f(t30)

dan815
 one year ago
Best ResponseYou've already chosen the best response.3no taht is what is figven

dan815
 one year ago
Best ResponseYou've already chosen the best response.3so i changed it to something that is f(t30)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443327270524:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0like what thats mean

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeap sweet as man, cheers!

dan815
 one year ago
Best ResponseYou've already chosen the best response.3greetings from Canada xD

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0still havent moved ay

dan815
 one year ago
Best ResponseYou've already chosen the best response.3how r things down in australia these days

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yea summer is coming, soo good. only like another 2 months then i'm in 4th yr.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hopefully get a job and i'll be done yesss

dan815
 one year ago
Best ResponseYou've already chosen the best response.3same story pretty much, gotta do capstone next year and land jobs

dan815
 one year ago
Best ResponseYou've already chosen the best response.3itsd like this project every engineer has to do for final year, i think u too

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh like research project

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah that will be aids

dan815
 one year ago
Best ResponseYou've already chosen the best response.3yeah its just htis one course that runs for the whole year and u have to work on it in your own time

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah thats our research project haha mine will focus more on mining but not sure what yet

dan815
 one year ago
Best ResponseYou've already chosen the best response.3oh you decided already xD i still got no idea

dan815
 one year ago
Best ResponseYou've already chosen the best response.3ill probably do some detection stuff i just wanna write code and make my partners do the more circuit stuff

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0my degree is focused in minerals processing/mining so its like i am forced to do something mining like haah yeah writing code sounds fun hahaha

dan815
 one year ago
Best ResponseYou've already chosen the best response.3what kind engineering is that?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0chemical eng. so gai

dan815
 one year ago
Best ResponseYou've already chosen the best response.3chemistry is too hard .

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0haha its pretty hectic but what i enjoy so its chill as.

dan815
 one year ago
Best ResponseYou've already chosen the best response.3u gotta actually learn like a lot of math to do real chem, but they dont teach all that math in a chem degree

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0too many people will fail hahaha

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0lots of science students aren't well educated in math anyway

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but enough of me speaking, i need some lunch! i'll let ya know how i go with this question after. cheers mate. peace
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