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Jhannybean
 one year ago
Practice with Logarithmic Inverse functions! For fun :)
\[f(x) = \frac{e^{2x}1}{2e^{2x}}\]
Jhannybean
 one year ago
Practice with Logarithmic Inverse functions! For fun :) \[f(x) = \frac{e^{2x}1}{2e^{2x}}\]

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.01/2 ln something.. give me a sec xD

anonymous
 one year ago
Best ResponseYou've already chosen the best response.01/2 ln ((2x+1)/(x+1)) ?

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.6Well, you dont even need to switch the variables first before simplifying I guess.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i'm used to it. teachers and their solutions. need to do their way if you want the mark :P

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.6\[y=\frac{e^{2x}1}{2e^{2x}}\]\[2yye^{2x} = e^{2x}1\]\[2y+1=e^{2x}+ye^{2x}\]\[e^{2x}(y+1)=2y+1\]\[e^{2x}=\frac{2y+1}{y+1}\]\[\ln e^{2x} =\ln\left(\frac{2y+1}{y+1}\right)\]\[2x=\ln\left(\frac{2y+1}{y+1}\right)\]\[f^{1}(x) = \ln\left[\left(\frac{2x+1}{x+1}\right)^{1/2} \right]\]
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