A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

AaronAndyson

  • one year ago

Derive the equivalent resistance of: Parallel Circuit. Series Circuit.

  • This Question is Closed
  1. dan815
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    what do u mean

  2. dan815
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    like actually work up to a resistance equation in circuits based off the collisions?

  3. AaronAndyson
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    It says use Ohm's law...

  4. dan815
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    okay phew

  5. dan815
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so we have V=IR atleast

  6. AaronAndyson
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Yes.

  7. dan815
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    now lets see what happens across 2 series resistors first

  8. dan815
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1443334063693:dw|

  9. dan815
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    can we use kirchoffs law too

  10. dan815
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    you know that if you sum up the voltages at every node around a look it has to equal 0

  11. dan815
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1443334173706:dw|

  12. dan815
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    now the current through resistor 1 is (v1-v2)/r1 current through resistor 2 is (v2)/r2

  13. dan815
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    and the current through both of these have to be equal as its just 1 line of wire

  14. AaronAndyson
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Um.You have used KCL/KVL?

  15. dan815
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ya is that not allowed

  16. AaronAndyson
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    They prefer to use Ohm's law..

  17. dan815
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    okay

  18. dan815
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1443334589905:dw|

  19. dan815
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    kvl is really ohms law

  20. dan815
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1443334664092:dw|

  21. dan815
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    we want to find R_T such that V=i*R_T where V is the source voltage

  22. dan815
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    which is V1 in this case

  23. dan815
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1443334764654:dw|

  24. dan815
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so R_T = R1+R2

  25. dan815
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    make sense?

  26. AaronAndyson
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Yep.

  27. dan815
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1443334898425:dw|

  28. dan815
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1443334924986:dw|

  29. dan815
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    you want to work on this one yourself?

  30. dan815
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I think you get the general idea right, you want to rearrange it in a form such that its i*(some resistor exprssion)

  31. AaronAndyson
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I guess.

  32. dan815
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    from the eequations above you can just solve for R_T

  33. AaronAndyson
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ?

  34. dan815
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ya just manipulation its not too bad

  35. dan815
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    good luck

  36. AaronAndyson
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    What about Parallel Circuit?

  37. dan815
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thats what im saying just play around with it

  38. dan815
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1443335708153:dw|

  39. dan815
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    solve for RT interms of R1 and R2

  40. dan815
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    given those ste of 4 equations

  41. dan815
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i dont have neuff space to write out the equations and work it in draw tool

  42. dan815
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    just do it on paper

  43. dan815
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1443335796472:dw|

  44. dan815
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1443335874626:dw|

  45. AaronAndyson
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Thanks..

  46. dan815
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    its missing steps

  47. dan815
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    just put them in

  48. AaronAndyson
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Getting conused..

  49. AaronAndyson
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    confused*

  50. dan815
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    what are you confused about

  51. AaronAndyson
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Everything ....

  52. dan815
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1443336583548:dw|

  53. dan815
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    do you get these 4 equations

  54. dan815
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    they are from ohms law

  55. dan815
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    technically KCL is there too but that is just a result of ohms law

  56. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.