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Diana.xL

  • one year ago

help

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  1. Diana.xL
    • one year ago
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    Find the value of the discriminant for each quadratic equation below. Show all steps needed to write the answer in simplest form, including substituting the values of a, b, and c in the discriminant formula. Then use the value to determine how many real number solutions each equation has. 2x^2 -3x = -5

  2. Diana.xL
    • one year ago
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    @ganeshie8

  3. ganeshie8
    • one year ago
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    Hey!

  4. Diana.xL
    • one year ago
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    hi

  5. ganeshie8
    • one year ago
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    do you know the "standard form" of quadratic equation ?

  6. Diana.xL
    • one year ago
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    2x^2 -3x = -5 would my equation be 2x^2 -3x +5 = 0?

  7. ganeshie8
    • one year ago
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    Exactly!

  8. anonymous
    • one year ago
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    Did you solve it out like they asked you to? I honestly forgot how to do this work because I'm now a sophomore in high school so...

  9. ganeshie8
    • one year ago
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    compare that with \(\color{red}{a}x^2 + \color{red}{b}x +\color{red}{c}=0\)

  10. ganeshie8
    • one year ago
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    \(\color{red}{a}=?\) \(\color{red}{b}=?\) \(\color{red}{c}=?\)

  11. anonymous
    • one year ago
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    Oh wait, never mind! You've got your answer. Never mind, you're on the right track. Carry on.

  12. Diana.xL
    • one year ago
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    a = 2, b = -3, c = 5

  13. ganeshie8
    • one year ago
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    Very good! next find the discriminant using the definition : discriminant = \(b^2-4ac\)

  14. ganeshie8
    • one year ago
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    simply plugin the values and simplify

  15. Diana.xL
    • one year ago
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    D = -3 – 4 (2)(5)

  16. anonymous
    • one year ago
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    *applauding*

  17. ganeshie8
    • one year ago
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    D = (-3)^2 – 4 (2)(5)

  18. anonymous
    • one year ago
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    *Great! You're an official mathematics genius!*

  19. Diana.xL
    • one year ago
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    oh ok. would my final answer be -31?

  20. ganeshie8
    • one year ago
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    Yes, so the discriminant is \(-31\), which is negative. so how many real solution the given quadratic equation will be having ?

  21. Diana.xL
    • one year ago
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    Since D is negative, root (D) doesn’t exist so the roots are unreal.

  22. ganeshie8
    • one year ago
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    Awesome! so there are no real roots for the given quadratic equation

  23. anonymous
    • one year ago
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    Okay so let me get this straight: So the asking person is asking this very confusing question which I DO NOT GET ANYMORE!!!! (Sorry for all caps). Ah... could someone teach me this stuff again? I know the powers pretty well but this particular problem like this. It's not like it's for homework anything but I really need help understanding this. I'm learning Geometry this year and I really just need some math help right now. Thanks!

  24. anonymous
    • one year ago
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    Hey! What about me @Diana.xL? That's just unsportsman like!

  25. ganeshie8
    • one year ago
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    @MeShipLad32 please open a new question and tag me I'd be happy to assist you :)

  26. anonymous
    • one year ago
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    nope im good

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