A community for students.
Here's the question you clicked on:
 0 viewing
Agent_A
 one year ago
Differential Equations problem.
Solve the initial Value Problem: (see the given, below)
I have the solution, and I know that we have to use integration by parts, but I'd like a better (clearer) solution, please. Just send me the whole thing. I want to see the way you solve it, in one run. Thanks!
Agent_A
 one year ago
Differential Equations problem. Solve the initial Value Problem: (see the given, below) I have the solution, and I know that we have to use integration by parts, but I'd like a better (clearer) solution, please. Just send me the whole thing. I want to see the way you solve it, in one run. Thanks!

This Question is Closed

Agent_A
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ dy }{ dt } = y + 2t\] \[y(0) = 2\]

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3As a start, multiply \(e^{t}\) through out

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3\(\dfrac{ dy }{ dt } = y + 2t\) \(\dfrac{ dy }{ dt } y = 2t\) \(\color{red}{e^{t}}\dfrac{ dy }{ dt }  \color{red}{e^{t}}y = \color{red}{e^{t}}2t\) Now, do you notice anythign special about the left hand side ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can this form be defined as \(\dfrac{dy}{dt}  P\cdot y = Q\) ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh I kind of see it now.

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3Yes, it's indeed a linear equation..

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2Note the integrating factor is \[e^{t}\] now what happens when you take the derivative of this \[(e^{t}y)'\]
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.