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Adi3

  • one year ago

Will medal please help. consider g(n) = -12-2n/3. Find g^-1(n)

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  1. Adi3
    • one year ago
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    @misty1212

  2. Adi3
    • one year ago
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    @ganeshie8

  3. Adi3
    • one year ago
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    @Jhannybean

  4. Jhannybean
    • one year ago
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    Is your function : \(g(n) = \dfrac{-12-2n}{3}\)?

  5. Adi3
    • one year ago
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    yes

  6. Adi3
    • one year ago
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    we need to find the inverse.

  7. Jhannybean
    • one year ago
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    So first graph it to see whether it's a one-to-one function, and it is. \[y = \frac{-12-2n}{3}\]Switch y and n \[n=\frac{-12-2y}{3}\]Now lets solve for y.

  8. Jhannybean
    • one year ago
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    I let my function \(g(n) = y\)

  9. Jhannybean
    • one year ago
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    What function do you get when you resolve for y?

  10. Adi3
    • one year ago
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    3n + 12 = -2y

  11. Jhannybean
    • one year ago
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    Good, and when you isolate y?

  12. Adi3
    • one year ago
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    that's where i reached till, i don't know what to do after that

  13. Jhannybean
    • one year ago
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    To isolate the variable y, what do you have to do to each side of the equation?

  14. Adi3
    • one year ago
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    divide by 2 i guess

  15. Jhannybean
    • one year ago
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    -2, and yes, you were partially right.

  16. Adi3
    • one year ago
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    so 3n + 12/-2 = y

  17. Jhannybean
    • one year ago
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    (3n + 12)/ -2 = y * It helps when you put parenthesis () around the numerator and denominator

  18. Adi3
    • one year ago
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    can I ask one more question please????

  19. Jhannybean
    • one year ago
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    We can simplify that function a bit by dividing both terms in the numerator by -2. ((3n)/-2) +(12/-2) = y

  20. Jhannybean
    • one year ago
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    Sure, I can try helping.

  21. Adi3
    • one year ago
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    ok, find the inverse of the equation f(x) = \[-\frac{ 4 }{ 7 }x - \frac{ 16 }{ 7 }\]

  22. Jhannybean
    • one year ago
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    \[y=\frac{-4x-16}{7}\]Same process, we switch x and y. \[x=\frac{-4y-16}{7}\] and now we resolve for y.

  23. Adi3
    • one year ago
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    7x +16 = -4x

  24. Adi3
    • one year ago
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    right?

  25. Jhannybean
    • one year ago
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    -4y*

  26. Adi3
    • one year ago
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    ohh yeah

  27. Jhannybean
    • one year ago
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    7x + 16 = -4y and now we've got to isolate y, just like before.

  28. Adi3
    • one year ago
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    \[\frac{ 7x+16 }{ -4 }\]

  29. Jhannybean
    • one year ago
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    That's right, and after resolving for y, we relabel it as \(f^{-1}(x)\)

  30. Adi3
    • one year ago
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    ok, can i ask further questions if i have doubt in them please?

  31. Jhannybean
    • one year ago
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    Sure, but im logging off for a while, although good luck on learning this!`

  32. Adi3
    • one year ago
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    when will you come back

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