@misty1212

@ganeshie8

@Jhannybean

4. Jhannybean

Is your function : $$g(n) = \dfrac{-12-2n}{3}$$?

yes

we need to find the inverse.

7. Jhannybean

So first graph it to see whether it's a one-to-one function, and it is. $y = \frac{-12-2n}{3}$Switch y and n $n=\frac{-12-2y}{3}$Now lets solve for y.

8. Jhannybean

I let my function $$g(n) = y$$

9. Jhannybean

What function do you get when you resolve for y?

3n + 12 = -2y

11. Jhannybean

Good, and when you isolate y?

that's where i reached till, i don't know what to do after that

13. Jhannybean

To isolate the variable y, what do you have to do to each side of the equation?

divide by 2 i guess

15. Jhannybean

-2, and yes, you were partially right.

so 3n + 12/-2 = y

17. Jhannybean

(3n + 12)/ -2 = y * It helps when you put parenthesis () around the numerator and denominator

19. Jhannybean

We can simplify that function a bit by dividing both terms in the numerator by -2. ((3n)/-2) +(12/-2) = y

20. Jhannybean

Sure, I can try helping.

ok, find the inverse of the equation f(x) = $-\frac{ 4 }{ 7 }x - \frac{ 16 }{ 7 }$

22. Jhannybean

$y=\frac{-4x-16}{7}$Same process, we switch x and y. $x=\frac{-4y-16}{7}$ and now we resolve for y.

7x +16 = -4x

right?

25. Jhannybean

-4y*

ohh yeah

27. Jhannybean

7x + 16 = -4y and now we've got to isolate y, just like before.

$\frac{ 7x+16 }{ -4 }$

29. Jhannybean

That's right, and after resolving for y, we relabel it as $$f^{-1}(x)$$

ok, can i ask further questions if i have doubt in them please?

31. Jhannybean

Sure, but im logging off for a while, although good luck on learning this!`