A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • one year ago

CHCl3, and acetone, (CH3)2CO, to create a solution where the mole fraction of chloroform, Xchloroform, is 0.155. The densities of chloroform and acetone are 1.48 g/mL and 0.791 g/mL, respectively.

  • This Question is Open
  1. aaronq
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    there is no question associated with what you've posted

  2. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Since the mole fraction of chloroform = 0.171, that means that: 0.171 = (moles chloroform) / (moles chloroform + moles acetone) Assume we have exactly 1 mole of chloroform, and let x = moles acetone. Then: 0.171 = 1/(1+x) 1+x = 1/0.171 = 5.85 x = 4.85 moles acetone Mass of 4.85 moles acetone = 4.85 mol X 58.1 g/mol = 282 g acetone molality = moles solute / kilogram solvent = 1 mol CHCl3 / 0.282 kg acetone = 3.55 molal Molarity = moles solute / L of solution Volume CHCl3 = 1 mol X 119.4 g/mol / 1.48 g/mL = 80.7 mL Volume acetone = 282 g / 0.791 g/mL = 356.5 mL Assuming that these two liquids mix ideally (the volume of the solution is equal to the sum of their individual volumes), then the total volume is 437 mL. So, the molarity of CHCl3 in the solution is 1 mol / 0.437 L = 2.29 Molar

  3. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.