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Adi3
 one year ago
Will medal
please help
find the inverse of
g(x) = (1)/x1 + 3
Adi3
 one year ago
Will medal please help find the inverse of g(x) = (1)/x1 + 3

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Adi3
 one year ago
Best ResponseYou've already chosen the best response.0\[\left(\begin{matrix}\\ \frac{ 1}{ x1 }\end{matrix}\right) + 3\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3g(x) is same as y so you can replace g(x) with y \[\huge\rm \color{ReD}{y}=\frac{ 1 }{ \color{blue}{x}1 } +3\] to find inverse `switch x and y` \[\huge\rm \color{blue}{x}=\frac{ 1 }{ \color{red}{y}1 } +3\] now solve for y

Adi3
 one year ago
Best ResponseYou've already chosen the best response.0ok, x  3 = \[\frac{ 1 }{ y1 }\]

Adi3
 one year ago
Best ResponseYou've already chosen the best response.0still on inverse, this is too much for me

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3sorry i was afk yes that's right \[\huge\rm x3=\frac{ 1 }{ y1}\] now how would you cancel out y1 from right side ?

imqwerty
 one year ago
Best ResponseYou've already chosen the best response.0write y in terms of x and then jst switch y and x :) function which u get is inverse

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3its already divided by 1 (1/y1 )to cancel it out you should do opposite of division

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3yes right multiply both sides by y1

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3multiply `both sides` by y1 \[\huge\rm (y1) (x3)=\frac{ 1 }{\cancel{y1} } \times \cancel{(y1)}\] we can cancel out y1 \[\large\rm (y1)(x3)=1\] now again to solve for y move `x3` to the right side

Adi3
 one year ago
Best ResponseYou've already chosen the best response.0ohh, then how to get y by itself?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3how would you cancel x3 from left side ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3right so divide both sides by x3 let me know what you get

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3it's multiplication( y1 ) times (x3) so yes you should divide

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3right now we should get the common denominator dw:1443366122753:dw

Adi3
 one year ago
Best ResponseYou've already chosen the best response.0OK, Can i ask a last question

Adi3
 one year ago
Best ResponseYou've already chosen the best response.0ok, thank you all. find the inverse of \[\frac{ 2 }{ 5}x  2\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3same steps try it first

imqwerty
 one year ago
Best ResponseYou've already chosen the best response.0think a way to isolate y

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3now \[x+2 =\frac{ 2 }{ 5 }y\] what would be the nexxt step ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3well first you need to get rid of the fraction

imqwerty
 one year ago
Best ResponseYou've already chosen the best response.0if u have 2x and u want just x then what number will u divide it by?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3\[\huge\rm x+2=\frac{ 2 }{ 5 }y\] to get rid of the fraction at right side what would u do ? remember it's 2 divided by 5

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3well i'm pretty sure they aren't looking for decimal answer

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3\[\huge\rm x+2=\frac{ 2 }{ 5 }y\] to get rid of the fraction at right side what would u do ? remember it's 2 divided by 5

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3how would you cancel out 5 from right side ?

Adi3
 one year ago
Best ResponseYou've already chosen the best response.0they do not want a answer in deci

imqwerty
 one year ago
Best ResponseYou've already chosen the best response.0see if u got something like this  \[x \times y\]and u wanna get rid of y then what u do is that just multiplay it by 1/y then u get\[x \times y \times \frac{ 1 }{ y }\] y and y get cut and u get ur x

Adi3
 one year ago
Best ResponseYou've already chosen the best response.0the answer is \[5  \frac{ 5 }{ 2 }x\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3yes right multiply both sides by 5 \[\huge\rm 5(x+2)=\frac{ 2 }{ 5 }y \times 5\] always first try to get rid of de fraction

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3can you explain plz how did you get 5 /2 and just 5 ?

Adi3
 one year ago
Best ResponseYou've already chosen the best response.0that is the answer, thats part i dont get it

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3yes right multiply both sides by 5 \[\huge\rm 5(x+2)=\frac{ 2 }{ 5 }y \times 5\] distribute parentheses by 5 5(x+2) = ???

Adi3
 one year ago
Best ResponseYou've already chosen the best response.0it is like 11:00 P.M here so i am gonna sleep, bye, cant understand anything right now. bye

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3right \[\huge\rm 5x+10 =2y\]last step

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.3there is only one step ........ 2 ` times ` y so to cancel it out divide by sides by 2

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.32 not just 2 and (5x+10)/2 can be written as 5x/2 + 10/2 \[\huge\rm \frac{ 5x+10 }{ 2}=\frac{ 5x }{ 2 }+\frac{ 10 }{ 2}\]now jsut simplify
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