A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
Differential Equation Problem: How Can i solve the Initial value problem. I am not sure if to use integrating factor? Equation below.
anonymous
 one year ago
Differential Equation Problem: How Can i solve the Initial value problem. I am not sure if to use integrating factor? Equation below.

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[2y \prime y^2 + 4 =0, y(0) = 0\]

amistre64
 one year ago
Best ResponseYou've already chosen the best response.0what methods are available to you?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0integrating factory and separable....

amistre64
 one year ago
Best ResponseYou've already chosen the best response.02 dy/dx = y^24 looks separable to me ... not sure if it makes life easier tho

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yep, i can work with that.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'll post the result soon.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It does not. It is complex.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443368763254:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm using that, A = 1/2 and b = 1/2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is it safe to say....dw:1443369358723:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but as y (0) = 0. I noticed that the equation initial condition will bring take the solution to.... e^(2c) = 1, but c does not exist since the ln(1) is undefined.

amistre64
 one year ago
Best ResponseYou've already chosen the best response.0as per the wolf ... might help you see where to go.

amistre64
 one year ago
Best ResponseYou've already chosen the best response.0A and B are + 1/4 right?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.0dy/(y^24) = dx/2 ln((y2)/(y+2))/4 = x/2 +C ln((y2)/(y+2)) = 2x +4C (y2)/(y+2) = e^(2x+4C) = C e^(2x) x=0,y=0 1 = C

amistre64
 one year ago
Best ResponseYou've already chosen the best response.0y2 = e^(2x) (y+2) y+ye^(2x) = 2e^(2x)+2 y(1+e^(2x)) = 2(1e^(2x)) ...

amistre64
 one year ago
Best ResponseYou've already chosen the best response.0mighta factored the rhs off by a negative in my head
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.