A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
Verify the identity.
cotangent of x to the second power divided by quantity cosecant of x plus one equals quantity one minus sine of x divided by sine of x
anonymous
 one year ago
Verify the identity. cotangent of x to the second power divided by quantity cosecant of x plus one equals quantity one minus sine of x divided by sine of x

This Question is Closed

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443371271009:dw

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0the original as written is not clear.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.012sin^2 x/ sin^2 x / 1+sin x/ sin x = 1 sin^2 x/ sinx * 1+ sinx

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2\[\huge\rm \frac{ \cot^2 (x) }{ \csc(x) +1 } =\frac{ 1\sin(x)}{ \sin(x)}\] like this ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I know if I factor 1(sinx)^2 I'll get 1+sinx and 1sinx

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2are you working on left or right side ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2alright first we can rewrite cot and csc in terms of sin and cos

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2csc = 1/sin right so cot = ??

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2yeah but we need to write in terms of sin cos

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2yes right \[\huge\rm \frac{ \frac{ \cos^2(x) }{ \sin^2(x) } }{ \color{reD}{\frac{ 1 }{ \sin(x) }+1} }\] now first deal with the denominator (red part)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2\[\frac{ 1 }{ \sin(x) }+1\] find the common denominator

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well 1/ sin = csc and 1+ csc = cot^2?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2yes right you can use the identity but i found the other one easy

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2but if you use the identity you still have to write csc in terms of sin and cos

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so what do I do, I know csc is 1/sin

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2\[\huge\rm \frac{ \frac{ \cos^2(x) }{ \sin^2(x) } }{ \color{reD}{\frac{ 1 }{ \sin(x) }+1} }\] now first deal with the denominator (red part) we need to find common denominator 1 is same as 1/1 so \[\frac{ 1}{ \sin(x)} +\frac{ 1 }{ 1 }\] common denomiantor is sin x right

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2\[\large\rm \frac{ 1 }{ \color{blue}{\sin(x)} }+\frac{ 1 }{ \color{red}{1}}\] \[\huge\rm \frac{ \color{red}{1}(1) +\color{blue}{sinx }(1)}{ \sin(x) }\] when we find common denominator we should multiply first fraction with the denominator of 2nd one and multiply the numerator of 2nd fraction with the denominator of first fraction

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2let me know if you have a question about that part ??^^^

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2alright \[\huge\rm \frac{ \frac{ \cos^2(x) }{ \sin^2(x) } }{ \color{reD}{\frac{ 1+sin(x) }{ \sin(x) }} }\] now change division to multiplication multiply first fraction with the `reciprocal` of the 2nd fraction

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2here is an example \[\huge\rm \frac{ \frac{ a }{ b } }{ \frac{ c }{ d } } =\frac{ a }{ b} \times \frac{ d }{ c }\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2no multiply top fraction with the reciprocal of bottom one what's reciprocal of 1+sinx/sin ???

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2right so multiply \[\huge\rm \frac{ \cos^2(x) }{\sin^2(x) } \times \frac{ \sin(x) }{1+\sin(x)}\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2sin^2 is same as sin times sin so you cancel it out

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2\[\huge\rm \frac{ \cos^2(x) }{\color{reD}{sin^2(x)} } \times \frac{ \sin(x) }{1+\sin(x)}\] sin^2 is same as sin times sin so you cancel it out \[\huge\rm \frac{ \cos^2(x) }{\color{reD}{sinx \times sinx} } \times \frac{ \sin(x) }{1+\sin(x)}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so does that mean sinx cancels out?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2\[\huge\rm \frac{ \cos^2(x) }{\color{reD}{sinx \times \cancel{sinx}} } \times \frac{\cancel{ \sin(x)} }{1+\sin(x)}\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2now use the identity cos^2(x) = ???

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0cos^2 = cosx * cosx?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2yes but we need identity

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2sin^2(x) +cos^2(x) =1 solve for cos^2(x)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh wait its a path. identity.

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2well ye just replace cos^2 with the identity then done

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2how would you cancel out sin^2 from left side \[\huge\rm sin^2x+\cos^2=1\] ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2subtract/add/divide /mutliply both sides by sin^2 x ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I don't understand, how? ^

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2yes i'm asking how would you cancel out sin^2x from left its just like simple equation

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2lets say we have x +y = 1 how would you solve for y ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you move x to the other side right?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2yes right what would you get ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0not enough info to solve, because x=?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2well lets say 2+x =1 how would you solve for x ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.02 both sides x = 1

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2yes right subtract 2 both sides so for this equation subtract sin2x both sides \[\huge\rm sin^2x+\cos^2=1\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2dw:1443375444006:dw what would you get at right side ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2yes right now u can replace cos^2x with that \[\huge\rm \frac{ \cos^2(x) }{\color{reD}{sinx \times \cancel{sinx}} } \times \frac{\cancel{ \sin(x)} }{1+\sin(x)}\] \[\huge\rm \frac{ 1sin^2(x)}{\color{reD}{sinx } } \times \frac{{ 1}}{1+\sin(x)}\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2\(\color{blue}{\text{Originally Posted by}}\) @clairvoyant1 I know if I factor 1(sinx)^2 I'll get 1+sinx and 1sinx \(\color{blue}{\text{End of Quote}}\) now as u said you can write 1sin^2x as (1+sinx)(1sinx)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2\[\huge\rm \frac{ (1+sin(x))(1sin(x))}{\color{reD}{sinx } } \times \frac{{ 1}}{1+\sin(x)}\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2you can cancel out something right after that done!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Computer froze logged in on my kindle Lol. Not quite

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2\[\huge\rm \frac{ (1+sin(x))(1sin(x))}{\color{reD}{sinx } } \times \frac{{ 1}}{1+\sin(x)}\] what can you cancel out ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2\[\large\rm \frac{ (1sin(x))\cancel{(1+sin(x))} }{\color{reD}{sinx } } \times \frac{{ 1}}{\cancel{1+\sin(x)}}\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2both sides are the same right ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok could you do a quick recap of what we just went over please.

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2first rewrite cot and csc in terms of sin and cos then we found the common denominator change division to multiplication use the identity cos^2=1sin^2 that's it

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2if you need the work you can reread the post :=) feel free to ask q

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank You so much for your patience and help :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Verify the identity. cos 4x + cos 2x = 2  2 sin2 2x  2 sin2 x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can you help me with this one.

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2i'm not sure about that one sorry i just know the basic :(

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2make new post so other people will b able to help chu

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Find the domain of the given function. f(x) = square root of quantity x plus three divided by quantity x plus eight times quantity x minus two. a) x > 0 b) All real numbers c) x ≥ 3, x ≠ 2 d) x ≠ 8, x ≠ 3, x ≠ 2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Verify the identity. cos 4x + cos 2x = 2  2 sin2 2x  2 sin2 x @campbell_st

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0well cos(4x )= 1  2sin^2(2x) and cos(2x) = 1 2sin^2(x) now make the substitution and simplify

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@campbell_st how would I do that?

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0exactly what it says... replace cos(4x) with the right hand side of the expression then the same with cos(2x) and collect like terms. what would probably be best, is to post it as a new question... as there is an lot of information that precedes the question you asked.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0alright I'll post it as a new question
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.