anonymous
  • anonymous
You have four large cointainers, the first one holds only 10 cent coins, the second 5 cent coins, the third 1 cent coins and the last one 0.5 cent coins. In how many ways can you select 20 coins from these?(combinatorics)
Mathematics
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
Im just thinking this equation, \[\left(\begin{matrix}n+r-1 \\ r\end{matrix}\right)\] cause im gonna make 20 selections(r = 20) among 4 elements(n = 4) \[\left(\begin{matrix}23 \\ 20\end{matrix}\right)\] is this completely wrong?
anonymous
  • anonymous
that is equal to 1771..
anonymous
  • anonymous
@IrishBoy123 you know combinatorics?

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IrishBoy123
  • IrishBoy123
looks right choosing with replacement, right?
anonymous
  • anonymous
Yea I think so, I dont really understand the difference yet.. @IrishBoy123
IrishBoy123
  • IrishBoy123
https://en.wikipedia.org/wiki/Combination it's not something i do/ have done very much; and as soon as you delve a little deeper i am no use. for this, the link explains it better than i could. ganeshie is great at this stuff [as he is at most things] and there are plenty of others here too that can help of course, i am always willing to help whenever i can :p

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