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ofmiceparade

  • one year ago

Solve x2 − 8x + 5 = 0 using the completing-the-square method.

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  1. ofmiceparade
    • one year ago
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    @hartnn Hi

  2. hartnn
    • one year ago
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    hello :) what have you tried?

  3. ofmiceparade
    • one year ago
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    i got x and square root of 11

  4. ofmiceparade
    • one year ago
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    I don't think i got it right

  5. hartnn
    • one year ago
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    ok, lets go step by step, x^2 -8x = -5 what did you add to both sides of this equation?

  6. ofmiceparade
    • one year ago
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    16

  7. hartnn
    • one year ago
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    good! so left side became the perfect square of (x-4) \((x-4)^2 = 16-5 \\ (x-4)^2=11\) now take square root on both sides

  8. ofmiceparade
    • one year ago
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    ?

  9. ofmiceparade
    • one year ago
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    11 can't be square rooted

  10. ofmiceparade
    • one year ago
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    and idk about x-4

  11. hartnn
    • one year ago
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    right, keep it as \(\Large \sqrt{11}\)

  12. ofmiceparade
    • one year ago
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    okay

  13. hartnn
    • one year ago
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    \(\sqrt{(x-4)^2} = x-4\)

  14. ofmiceparade
    • one year ago
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    okay so x-4 = square root of 11

  15. hartnn
    • one year ago
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    \(\Large x-4 =\pm \sqrt {11}\)

  16. hartnn
    • one year ago
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    because there would be a negative root too

  17. ofmiceparade
    • one year ago
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    okay but my answer choices are x = negative four plus or minus the square root of eleven x = four plus or minus the square root of eleven x = negative four plus or minus the square root of five x = four plus or minus the square root of five

  18. ofmiceparade
    • one year ago
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    That isn't "x ="

  19. hartnn
    • one year ago
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    add 4 on both sides

  20. ofmiceparade
    • one year ago
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    OHHHH

  21. hartnn
    • one year ago
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    \(\Large x = 4\pm \sqrt{11}\)

  22. ofmiceparade
    • one year ago
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    OMG I LOVE YOU <3333333333333333333333333333333333

  23. ofmiceparade
    • one year ago
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    No hetero

  24. hartnn
    • one year ago
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    me too :) welcome ^_^

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