ofmiceparade
  • ofmiceparade
Solve x2 − 8x + 5 = 0 using the completing-the-square method.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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ofmiceparade
  • ofmiceparade
@hartnn Hi
hartnn
  • hartnn
hello :) what have you tried?
ofmiceparade
  • ofmiceparade
i got x and square root of 11

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More answers

ofmiceparade
  • ofmiceparade
I don't think i got it right
hartnn
  • hartnn
ok, lets go step by step, x^2 -8x = -5 what did you add to both sides of this equation?
ofmiceparade
  • ofmiceparade
16
hartnn
  • hartnn
good! so left side became the perfect square of (x-4) \((x-4)^2 = 16-5 \\ (x-4)^2=11\) now take square root on both sides
ofmiceparade
  • ofmiceparade
?
ofmiceparade
  • ofmiceparade
11 can't be square rooted
ofmiceparade
  • ofmiceparade
and idk about x-4
hartnn
  • hartnn
right, keep it as \(\Large \sqrt{11}\)
ofmiceparade
  • ofmiceparade
okay
hartnn
  • hartnn
\(\sqrt{(x-4)^2} = x-4\)
ofmiceparade
  • ofmiceparade
okay so x-4 = square root of 11
hartnn
  • hartnn
\(\Large x-4 =\pm \sqrt {11}\)
hartnn
  • hartnn
because there would be a negative root too
ofmiceparade
  • ofmiceparade
okay but my answer choices are x = negative four plus or minus the square root of eleven x = four plus or minus the square root of eleven x = negative four plus or minus the square root of five x = four plus or minus the square root of five
ofmiceparade
  • ofmiceparade
That isn't "x ="
hartnn
  • hartnn
add 4 on both sides
ofmiceparade
  • ofmiceparade
OHHHH
hartnn
  • hartnn
\(\Large x = 4\pm \sqrt{11}\)
ofmiceparade
  • ofmiceparade
OMG I LOVE YOU <3333333333333333333333333333333333
ofmiceparade
  • ofmiceparade
No hetero
hartnn
  • hartnn
me too :) welcome ^_^

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