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I am about to upload what I have done... don;t know where to go from there

I think your looking at the wrong problem.

I have that one finished

I am working on part III

oh, oops -- I misread the title and thought it said part II

Lol No big deal, could you look at my work?

\[\sqrt{+__+__}\]

So I can't just say that its the magnitude of one plus the magnitude of the other etc.

now \(\|u\|=\|v\|=2\) and \(\|w\|=3\) gives us $$\|u+v+w\|=\sqrt{2^2+2^2+3^2}=\sqrt{17}$$

I am confused

indeed, you can't (in general) say that the magnitude of the sum is the sum of the magnitudes

Real quick how do you create the brackets that go around the inner product?

\langle and \rangle

$$\text{\langle}\implies\langle\\\text{\rangle}\implies\rangle$$

\[\sqrt{+__+__}\neq \sqrt{}+\sqrt{}+\sqrt{__}\]__

But in your explanation you made \[=\left| v \right|\]

indeed, that is not true

I meant for that absolute v to have double bars.....

but the definition in my book shows that \[\left| \right|v \left| \right|=\sqrt{}\]