Find the value of the following expression

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Find the value of the following expression

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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have to use a couple of the exponent rules
\[\large [u^a]^b = u^{a*b}\] \[u^a * u^b = u^{a+b}\]
@danjs I know that but I cant seem to get the answer right
k, let me enter the thing
\[\large (2^8 * 3^{-5}*6^0)^{-2}*[\frac{ 3^{-2} }{ 2^3 }]^4*2^{28}\]
@DanJS I know what the expression is I need the answer...
i can give you the answer, but how would you know where you went wrong to get there
ill ask my teacher tom
i can show you how to apply the exponent properties and get to the answer
You can only apply the exponent rules if the base is the same... I would do the parenthesis part first, and a power raised to a power is where you multiply the powers to simplify \[\large (2^8 * 3^{-5}*6^0)^{-2}*\frac{ 3^{-2*4} }{ 2^{3*4} }*2^{28}\]
-40?
The parenthesis part left has 6^0 in it, something to the zero power is always 1. Here again you apply the power raised to a power rule to simplify \[\large (2^{-16} * 3^{10}*1)*\frac{ 3^{-8} }{ 2^{12} }*2^{28}\]
not sure, i didnt calculate anything
You can change the side of a fraction an exponential is on by changing the sign of it's exponent, move the 2^12 to the numorator, you are left with just a string of terms being multiplied
\[\large 2^{-16} * 3^{10}*1* 3^{-8}* 2^{-12} *2^{28}\] combine the powers of the like bases, then it is simplified

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