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anonymous
 one year ago
What is y^4y^3=0
How do you factor this out?
anonymous
 one year ago
What is y^4y^3=0 How do you factor this out?

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Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1what's the common factor ? well its soo easy to find common factor of variables `variable with the smallest degree would be the common factor `

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How would you do it though?

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0you are really multiplying by y^2 / y^2 this will pull a y^2 term out of each of those

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1we should take out the common factor so first ) what's a common factor ???

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0left with y^2*(each divided by y^2)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@DanJS my book did it by y(y^31) =y(y1)(y^2+y+1) I dont understand how they do it

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1well ^^take out y from y^4 y^3 \[\huge\rm y(y^31)\] y^31 is same as (y^3 1^3)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1then you can apply the rule \[\huge\rm x^3y^3=(xy)(x^2+xy+y^2)\]

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0is the original problem y^4  y^3

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1i guess it's y(y^31) ??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Shouldn't it factor out as y^3(y1)?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Doesn't y(y^31) = y^4y

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1ye....... and then set it equal to zero if you want to solve to for y but factor is y^3(y1) that looks correct 2 me :/

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443386881935:dw

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0\(y^4  y^3 = 0\) \(y^3(y  1) = 0\) \(y^3 = 0\) or \(y  1 = 0\) Now solve both equations for y.

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\(\color{blue}{\text{Originally Posted by}}\) @Anzhbar my book did it by y(y^31) =y(y1)(y^2+y+1) I dont understand how they do it \(\color{blue}{\text{End of Quote}}\) i guess you're looking at the wrong question .....:/

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443387331458:dw
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