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anonymous

  • one year ago

What is y^4-y^3=0 How do you factor this out?

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  1. Nnesha
    • one year ago
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    what's the common factor ? well its soo easy to find common factor of variables `variable with the smallest degree would be the common factor `

  2. anonymous
    • one year ago
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    How would you do it though?

  3. DanJS
    • one year ago
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    you are really multiplying by y^2 / y^2 this will pull a y^2 term out of each of those

  4. Nnesha
    • one year ago
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    we should take out the common factor so first ) what's a common factor ???

  5. DanJS
    • one year ago
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    left with y^2*(each divided by y^2)

  6. anonymous
    • one year ago
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    @DanJS my book did it by y(y^3-1) =y(y-1)(y^2+y+1) I dont understand how they do it

  7. Nnesha
    • one year ago
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    well ^^take out y from y^4 -y^3 \[\huge\rm y(y^3-1)\] y^3-1 is same as (y^3 -1^3)

  8. Nnesha
    • one year ago
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    then you can apply the rule \[\huge\rm x^3-y^3=(x-y)(x^2+xy+y^2)\]

  9. DanJS
    • one year ago
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    is the original problem y^4 - y^3

  10. DanJS
    • one year ago
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    = y^3 * (y-1) = 0

  11. DanJS
    • one year ago
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    y is 0 or 1

  12. anonymous
    • one year ago
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    Yes

  13. Nnesha
    • one year ago
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    i guess it's y(y^3-1) ??

  14. anonymous
    • one year ago
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    Shouldn't it factor out as y^3(y-1)?

  15. anonymous
    • one year ago
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    Doesn't y(y^3-1) = y^4-y

  16. Nnesha
    • one year ago
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    ye....... and then set it equal to zero if you want to solve to for y but factor is y^3(y-1) that looks correct 2 me :/

  17. mathstudent55
    • one year ago
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    |dw:1443386881935:dw|

  18. mathstudent55
    • one year ago
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    \(y^4 - y^3 = 0\) \(y^3(y - 1) = 0\) \(y^3 = 0\) or \(y - 1 = 0\) Now solve both equations for y.

  19. Nnesha
    • one year ago
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    \(\color{blue}{\text{Originally Posted by}}\) @Anzhbar my book did it by y(y^3-1) =y(y-1)(y^2+y+1) I dont understand how they do it \(\color{blue}{\text{End of Quote}}\) i guess you're looking at the wrong question .....:/

  20. mathstudent55
    • one year ago
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    |dw:1443387331458:dw|

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