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anonymous
 one year ago
Calculate the mass (in grams) of sodium in 8.5 g Na3PO4
anonymous
 one year ago
Calculate the mass (in grams) of sodium in 8.5 g Na3PO4

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Frostbite
 one year ago
Best ResponseYou've already chosen the best response.1Hey there. So the way we solve this problem is simply by calculating the amount of substance, \(n\), [mol] of trisodium phosphate, we then notice the ratio between sodium and trisodium phosphate is 3, therefor you need to multiple the amount of substance of trisodium phosphate by 3 to obtain the amount of substance for sodium. Finally we calculate the mass of sodium by multiplying with the molar mass of sodium. Think you can do that, or shall we look at it together?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Is it ok if you wrote it by number,?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@frostbite And thanks

Frostbite
 one year ago
Best ResponseYou've already chosen the best response.1Else let me help a little more: We want to find the amount of substance of trisodium phosphate (Na3PO4), we do this using the relation between the molar mass and the mass of a substance: \[\large n(\text{Na}_3\text{PO}_4)=\frac{ m(\text{Na}_3\text{PO}_4) }{ M(\text{Na}_3\text{PO}_4) }\] Knowing the amount of substance for trisodium phosphate, we can calculate the amount of substance for sodium, you can imagine this reaction simply things: \[\large \text{Na}_3 \text{PO}_4 \rightarrow 3 ~ \text{Na} ~ + \text{P} + ~ 4 ~ \text{O}\] The ratio from the equation thereby becomes: \[\large \frac{ n(\text{Na}_3) }{ n(\text{Na}_3\text{PO}_4) }=3 \rightarrow n(\text{Na}_3\text{PO}_4) = \frac{n(\text{Na})}{3}\] insert into previous relation we get: \[\large \frac{ n(\text{Na}) }{ 3 }=\frac{ m(\text{Na}_3\text{PO}_4) }{ M(\text{Na}_3\text{PO}_4) }\] Using the relation between the amount of substance for sodium \( n(\text{Na})\) and the mass of sodium we can write: \[\large n(\text{Na})=\frac{ m(\text{Na}) }{ M(\text{Na}) }\] Insert into previous relation we get: \[\large \frac{ m(\text{Na}) }{ M(\text{Na}) } \frac{ 1 }{3 } = \frac{ m(\text{Na}_3\text{PO}_4) }{ M(\text{Na}_3\text{PO}_4)}\] Rearrange and solve for the mass of sodium: \[\Large m(\text{Na})=\frac{ M(\text{Na}) ~ 3 ~ m(\text{Na}_3\text{PO}_4) }{ M(\text{Na}_3\text{PO}_4) }\]

Frostbite
 one year ago
Best ResponseYou've already chosen the best response.1So you know what the mass of trisodium phosphate (Na3PO4) is. And you can calculate the molar mass of sodium and trisodium phosphate like this: \[\large M(\text{Na})=22.9 ~ \frac{ \text{g} }{ \text{mol} }\] And: \[\large M(\text{Na}_3 \text{PO}_4)=3 \times M(\text{Na})+M(\text{P})+4 \times M(\text{O})\] All the M(X) can be found in the periodic table and is the mass of each element :)

Frostbite
 one year ago
Best ResponseYou've already chosen the best response.1You can also look up the molar masses on the wiki.

Frostbite
 one year ago
Best ResponseYou've already chosen the best response.1Use the last relation and you should be good. I just hope I could make you understand so if you face a similar problem you could solve it with no issue.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@frostbite Thanks alot ππ»

Frostbite
 one year ago
Best ResponseYou've already chosen the best response.1No problem at all. If you like I can offer you to try calculate the number and then I check before you hand it in.

Frostbite
 one year ago
Best ResponseYou've already chosen the best response.1Got to an answer? :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@frostbite I appreciate it ..thank you
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