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chrisplusian

  • one year ago

Linear algebra...dealing with inner product and finding the smallest interior angle. See attachments please...

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  1. chrisplusian
    • one year ago
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    1 Attachment
  2. chrisplusian
    • one year ago
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    1 Attachment
  3. chrisplusian
    • one year ago
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    That is the question and the answer that I came up with. It is obviously wrong because a triangle does not have 249.96 degrees on its interior. If you can point out what I am doing wrong I would appreciate it

  4. amistre64
    • one year ago
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    so the subtraction is to define BC ?

  5. amistre64
    • one year ago
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    3 2 -3 8 -1 1 ------- 24-2-3 = 19 is our product of AB and AC 3 2 -3 3 2 -3 ------- 9+4+6 = 19, sqrt(19) 8 -1 1 8 -1 1 ------ 64+1+1 = 66. sqrt(66) cos(a1) = 19/sqrt(19*66) a1 = 57.55 degrees

  6. chrisplusian
    • one year ago
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    No if you look at the first attachment that was the problem. What is on the other attachment is me trying to work it out. If What I have is wrong tell me

  7. amistre64
    • one year ago
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    ac.ab is messed up

  8. amistre64
    • one year ago
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    my sqrt19 is messed up too ... add instead of multiplied

  9. amistre64
    • one year ago
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    <ac,ab> is not 11 ; first value is 3, not 2 <ba,bc>, third term is 3(4) is not -12 you have some transcription errors and sign errors thruout that need addressed.

  10. IrishBoy123
    • one year ago
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    .

  11. chrisplusian
    • one year ago
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    Yeah I made quite a few mistakes there let me try that again with the right numbers and see if it works

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