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chrisplusian
 one year ago
Linear algebra...dealing with inner product and finding the smallest interior angle.
See attachments please...
chrisplusian
 one year ago
Linear algebra...dealing with inner product and finding the smallest interior angle. See attachments please...

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chrisplusian
 one year ago
Best ResponseYou've already chosen the best response.0That is the question and the answer that I came up with. It is obviously wrong because a triangle does not have 249.96 degrees on its interior. If you can point out what I am doing wrong I would appreciate it

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1so the subtraction is to define BC ?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.13 2 3 8 1 1  2423 = 19 is our product of AB and AC 3 2 3 3 2 3  9+4+6 = 19, sqrt(19) 8 1 1 8 1 1  64+1+1 = 66. sqrt(66) cos(a1) = 19/sqrt(19*66) a1 = 57.55 degrees

chrisplusian
 one year ago
Best ResponseYou've already chosen the best response.0No if you look at the first attachment that was the problem. What is on the other attachment is me trying to work it out. If What I have is wrong tell me

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1my sqrt19 is messed up too ... add instead of multiplied

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1<ac,ab> is not 11 ; first value is 3, not 2 <ba,bc>, third term is 3(4) is not 12 you have some transcription errors and sign errors thruout that need addressed.

chrisplusian
 one year ago
Best ResponseYou've already chosen the best response.0Yeah I made quite a few mistakes there let me try that again with the right numbers and see if it works
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