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anonymous

  • one year ago

Prove: tan^2 θ•cos^2 θ + cos^2 θ = 1. You must show all work. any help please?

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  1. anonymous
    • one year ago
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    Okay so this is what grade?

  2. Nnesha
    • one year ago
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    write tan^2 in terms of sin cosine tan = what ?

  3. anonymous
    • one year ago
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    this is 11th grade math. trigonometry in Algebra 2

  4. anonymous
    • one year ago
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    i have no clue

  5. Nnesha
    • one year ago
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    alright first you need to know the definition of sin /cos and tan 1/csc ,1/ sec ,1/cot are reciprocal of sin , cos and sin \[\tan =\frac{ 1 }{ \cot }\] or you can say tan =sin/cos same thing

  6. Nnesha
    • one year ago
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    \[\tan=\frac{ \sin }{ \cos } ~~~\cos= \frac{ 1 }{ \sec }~~~\sin=\frac{ 1 }{ \csc }\] for that question we just need tan=sin/cos

  7. anonymous
    • one year ago
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    oh, right... x/y

  8. Nnesha
    • one year ago
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    \[\huge\rm \color{ReD}{tan^2 \theta} • \cos^2 \theta+\cos^2 \theta=1\] we can rewrite tan^2 in terms of sin cosine \[\huge\rm \color{Red}{\frac{ \sin^2 \theta }{ \cos^2 \theta }}• \cos^2 \theta+\cos^2 \theta=1\]

  9. anonymous
    • one year ago
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    which would eliminate the cos^2

  10. Nnesha
    • one year ago
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    yes right \[\huge\rm \color{Red}{\frac{\sin^2 \theta }{\cancel{ \cos^2 \theta} }}• \cancel {\cos^2 \theta}+\cos^2 \theta=1\] left with \[\huge\rm\color{blue}{ sin^2 \theta +\cos^2} =1\] you should b familiar with that special identity

  11. anonymous
    • one year ago
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    okay, thanks

  12. Nnesha
    • one year ago
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    cos^2 theta **

  13. Nnesha
    • one year ago
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    sin^2 +cos^2 equal to what ??

  14. imqwerty
    • one year ago
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    1

  15. imqwerty
    • one year ago
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    hey m jst guessing ( ͡° ͜ʖ ͡° )

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