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anonymous
 one year ago
An apartment complex contains 230 apartments each having 1, 2 or 3 bedrooms. The number of 2bedroom apartments is 10 more than 3 times the number of 3bedroom apartments. The number of 1bedroom apartmenst is twice the number of 2bedroom apartments. How many apartments of each kind are in the complex? Please answer with procedure
anonymous
 one year ago
An apartment complex contains 230 apartments each having 1, 2 or 3 bedrooms. The number of 2bedroom apartments is 10 more than 3 times the number of 3bedroom apartments. The number of 1bedroom apartmenst is twice the number of 2bedroom apartments. How many apartments of each kind are in the complex? Please answer with procedure

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jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2Let x = number of 1bedroom apartments y = number of 2bedroom apartments z = number of 3bedroom apartments

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2`The number of 2bedroom apartments is 10 more than 3 times the number of 3bedroom apartments` gives the equation y = 3z + 10

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2`The number of 1bedroom apartmenst is twice the number of 2bedroom apartments` means x = 2y

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2`An apartment complex contains 230 apartments each having 1, 2 or 3 bedrooms` so x+y+z = 230

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2you have this system of equations \[\Large \begin{cases}y = 3z + 10\\x = 2y\\x+y+z = 230\end{cases}\]

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2Do you see how to solve?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Its the only one i cant seem to get

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2since y = 3z+10, we can replace the y in x = 2y with 3z+10 x = 2y x = 2*(3z+10) ... replace y with 3z+10 x = 6z+20

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2x+y+z = 230 6z+20+y+z = 230 ... replace x with 6z+20 6z+20+3z+10+z = 230 ... replace y with 3z+10

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.2now solve `6z+20+3z+10+z = 230` for z

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0omg thanks brother You helped me out a lot today
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