At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
post your question please
find the exact values of the trig functions of the angle below. (Use the Pythagorean Theorem to find the third side)
There is a triangle with a hypotenuse of 41 and an adjacent of 9, the opposite is missing.
|dw:1443394526440:dw| something like this?
did I get the drawing right or...?
ok, do you know how to find the length of the missing side?
yeah it's where you do a^2 + b^2 = c^2 and then you square root it
ok, so what's the missing side?
I got 42, but my pre calc book got 40, so I really don't know what I did wrong
9^2 + x^2 = 41^2
solve for x
ohh, okay. I got 40 as my answer. Thank you so much
yup, x = 40 so now we have all three sides, now comes the easy part|dw:1443395117726:dw|
so, our trig functions are: sin(theta) = opposite/hypotenuse cos(theta) = adjacent/hypotenuse tan(theta) = opposite/adjacent
csc(theta) = hypotenuse/opposite sec(theta) = hypotenuse/adjacent cot(theta) = adjacent/opposite
now all you need to do is look at the triangle and plug in the numbers where they belong
I know how to do those parts. They are the easiest. :b but I have another triangle with the opoosite being 15, the adjacent being 8, & the hypotenuse missing. I did the eexact same thing in order to solve it , but I got 12.68 and my book got 17.
15^2 + 8^2 = x^2
so the opposite and adjacent are always a & b and the hypotenuse is always c?