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So in this example f(x)=6x^2+5, if I told you find f(2) would you know what to do?

yes its just plugging it in to the function

Then continue to manipulate algebraically

\[f(a+h)=6(a+h)^2 +5 =6(a^2 +2ah +h^2)+5\]

\[6(a^2 +2ah +h^2)+5 = 6a^2 +12ah +6h^2 +5\]

and then subtract that from 6a^2+5?

yes :)

so i got 12ah+6h^2+10

so divide by h?

\[\frac{ 6a^2 +12ah +6h+5-(6a^2 +5) }{ h }\]

\[\frac{ 12ah +6h }{ h }=\frac{ h(12a+6) }{ h }=12a+6\]

Hope that helps

im sorry but it says its wrong

ohhhh okay got it, thanks!

Your welcome

It should only be \(\huge 12a\).

You're finding the derivative, right?

no his answer was right

Ok if that's what you're saying.