## anonymous one year ago Having trouble understanding these steps for one of my classes:

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1. anonymous

$zl = \theta*z(h-l)-\theta*G$ to $zl*(1+ \theta) = \theta*zh-\theta*G$ to $l = \theta/(1+\theta)*(h-G/z)$

2. anonymous

Where all are constants except l

3. anonymous

Okay I get that, thanks a lot. Can you explain the last part too for us?

4. anonymous

hmmm what part again?

5. anonymous

From zl(1+Theta) = Thetazh -ThetaG to the answer where l is solved for

6. anonymous

7. anonymous

hmmm

8. anonymous

sec

9. anonymous

No problem appreciate the help friend

10. anonymous

hmmm hmm lemme start off you want $$\bf zl = \theta*z(h-l)-\theta*G\qquad to\qquad l = \cfrac{\theta}{1+\theta}\cdot \cfrac{h-G}{z}$$ right?

11. anonymous

yes