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anonymous

  • one year ago

Having trouble understanding these steps for one of my classes:

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  1. anonymous
    • one year ago
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    \[zl = \theta*z(h-l)-\theta*G\] to \[zl*(1+ \theta) = \theta*zh-\theta*G\] to \[l = \theta/(1+\theta)*(h-G/z)\]

  2. anonymous
    • one year ago
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    Where all are constants except l

  3. anonymous
    • one year ago
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    Okay I get that, thanks a lot. Can you explain the last part too for us?

  4. jdoe0001
    • one year ago
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    hmmm what part again?

  5. anonymous
    • one year ago
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    From zl(1+Theta) = Thetazh -ThetaG to the answer where l is solved for

  6. anonymous
    • one year ago
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    l=θ/(1+θ)∗(h−G/z) is the right answer

  7. jdoe0001
    • one year ago
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    hmmm

  8. jdoe0001
    • one year ago
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    sec

  9. anonymous
    • one year ago
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    No problem appreciate the help friend

  10. jdoe0001
    • one year ago
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    hmmm hmm lemme start off you want \(\bf zl = \theta*z(h-l)-\theta*G\qquad to\qquad l = \cfrac{\theta}{1+\theta}\cdot \cfrac{h-G}{z}\) right?

  11. anonymous
    • one year ago
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    yes

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