Let A = {4, 5, 6} and B = {5, 6, 7} and define relations R, S, and T from A to B as follows: For all (x, y) ∈ A × B, (x, y) ∈ R means that x ≥ y. (x, y) ∈ S means that x − y/ 2 is an integer. T = {(4, 7), (6, 5), (6, 7)}. a. Draw arrow diagrams for R, S, and T . b. Indicate whether any of the relations R, S, and T are functions.

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Let A = {4, 5, 6} and B = {5, 6, 7} and define relations R, S, and T from A to B as follows: For all (x, y) ∈ A × B, (x, y) ∈ R means that x ≥ y. (x, y) ∈ S means that x − y/ 2 is an integer. T = {(4, 7), (6, 5), (6, 7)}. a. Draw arrow diagrams for R, S, and T . b. Indicate whether any of the relations R, S, and T are functions.

Discrete Math
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Do you know what the notation `(x, y) ∈ A × B` means?
yes
coordinates that belong to the cross section of A and b

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or maybe not lol. Could you explain just in case i may have a gap with that
A X B is a set of all ordered pairs (x,y) such that x is in A, y is in B what I like to do is make a table that is 3x3. 3 rows because there are 3 elements in B 3 columns because there are 3 elements in A along the top, I put the elements of set A along the left side, I put the elements of set B |dw:1443397063622:dw|
I got R correctly. but i dont get the right answer for S
For R i just followed the condition
actually it might be better to swap the places of A and B |dw:1443397190016:dw|
to fill out this table, we simply list the points (x,y) where x comes from A, y comes from B eg: (4,5) goes in the top left because we have 4 from A, and 5 from B |dw:1443397266909:dw|
are you able to fill out the rest of this table?
yes i think i got it. Thanks you a lot !
ok tell me what you get

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