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which method u prefer to use
what i meant was elimination , substitution ... matrix
Subtract the 2nd from the 1st to get y-z=-7
Then you'll have : y-z =-7 y+z=47 Add the equations together to eliminate z then solve for y.
That's the easiest approach here.
y = 0 z = 0
-7 + 47 = 40
You should have gotten 2y=40 not y=0
oh sorry i subtracted
Yes I know. Be careful
whats the next step
@LynFran do you understand this
here ur substitution method and yes i know all 3 method thats y i ask which u prefer ok we can rewrite the 3rd equation as y=47-z we can also rrewrite the 2nd equation to get x=39-z now subs the 2 equations about into the 1st equation to get x+y=32 39-z+47-z=32 86-2z=32 86-32=2z 54=2z 27=z now sub z=27 into the 3rd equation above to get y+z=47 y+27=47 y=47-27 y=20 now sub y=20 into 1st equation to get x+y=32 x+20=32 x=32-20 x=12
Elimination is the simplest and most efficient method to Use here.
yea i agree but @harz360 prefer substitution
The goal is to solve using the least amount of steps
when i see all the steps thats when i understand it
It's a matter of efficiency not preference.
I would have taken the first 2 equations...and eliminated the x's...then go from there
but thanks a lott @LynFran
@Hero thanks so much
here the elimination method using 1st and 2nd equation subtract we get y-z=32-39 now using the 3rd equation subtract y-z=-7 y+z=47 we get -z-z=-7-47 -2z=-54 z=-54/-2 z=27 now sub z=27 into 3rd equation we get y+z=47 y=47-27 y=20 now sub y=20 in 1st equation we get x+y=32 x+20=32 x=32-20 x=12
this method seems confusing by the subtraction method seems easier to follow
That WAS the subtraction method. Lyn just wrote it awkwardly
ohh i c
no thats the elimination method in details
ohh i understand both when i see the steps which lyn has shown nicely