- anonymous

the diameter of circle symbol z is 5 in. what is the area in terms of pi ?

- schrodinger

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- anonymous

##### 1 Attachment

- Nnesha

what's the formula to find AREA of a circle ??

- anonymous

a=pi radius squared

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## More answers

- Nnesha

yes right
and diameter is half of radius
you can use this formula to find radius \[\huge\rm r=\frac{ d }{ 2 }\]

- anonymous

so 2.5 in squared ?

- Nnesha

yes right take square of 2.5

- anonymous

huh?

- Nnesha

well radius is 2.5 right ?

- anonymous

yes it is

- Nnesha

\[\huge\rm A =\pi r^2\]

- Nnesha

substitute r for 2.5 ^^

- anonymous

ok i get 6.25

- Nnesha

right

- Nnesha

and we have to write it interms of pi

- anonymous

ok so 6.25pi in squared

- anonymous

can you help me with another one @Nnesha

- Nnesha

i willlll try not sure:=)

- anonymous

can you help @DanJS

- DanJS

ok

- anonymous

##### 1 Attachment

- anonymous

this is the question

- DanJS

the point C(x,y) is 3/4 the way from A to B along a line...
youc an set up 2 equations involving x and y and solve
or...

- DanJS

since it is a line with a constant slope , the x and y components of that form a right triangle
realizing that the relation between the lengths of each side by the pythagorean theorem
c^2 = a^2 + b^2
if you shrink the hypotenuse down by 3/4 you have to do that to the other terms too

- DanJS

(3/4)c^2 = (3/4)*a^2 + (3/4)*b^2

- anonymous

ok

- DanJS

so you can just look and see the change in x coordinate, and find 3/4 that, and add that to the start value

- DanJS

Same for y coordinate

- anonymous

ok so how do i this then ?

- DanJS

The length in the x direction from A to B is 16, 3/4 of that is 12
start at A and move 12 in the X direction, that is the x coordinate of C

- DanJS

do the same for the Y direction

- anonymous

so 2,0

- anonymous

thats what i got

- DanJS

yeah, sounds good

- DanJS

It is just basically shrinking a right triangle by 25% then seeing where it lies on the coordinates

- anonymous

so i got that right ?

- DanJS

or you can do it by setting up 2 equations involving x and y in the point N, then solving for the x and y

- DanJS

Distance AC = 3/4 * Distance AB
and
equation of the line through AB

- anonymous

ok cool but am i right ?

- DanJS

yes, you can check by just calculating the distances AB and AC and check if they are correct

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