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The solution does not have 1/2's, not sure where exactly my mistake is xD

That should say \[\psi_x = A ~~~\text{and}~~~\psi_y = B\]

So you can label your two functions anything? M and N or P and Q?

*Scratches head* I can't find the mistake..the answer should be \[xe^{2y}-\ln|y|=C\]

The M and N is just a way to find whether or not it's an exact equation

but yeah essentially, M(x,y)dx+N(x,y)dy = 0

Oh i see,kind of like test values, but instead of values you have functions.

I hate M and N crap, it's basically a waste of extra notation just cause 'it might not be exact' lol

Haha, I'm just doing it the way I learnt

I did that in calc 2, but omg you just gave me an idea to check my solution

multiply by 2
R.H.S=2C=C'

C'=C=A CONSTANT.

What do you mean @Empty
Haha and if that's it...@surjithayer

\[xe ^{2y}-\ln y=2C=c\]

ok then

You answered all my questions even ones I hadn't asked, thanks a lot @oldrin.bataku that was great!