A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

cheska_P

  • one year ago

I'm a visual learning, can some one please work this out so I can see how you get the answer? Physics exam in two days! The velocity v(t) of a particle as a function of time is given by v(t) = (2.3 m/s) + (4.1 m/s2)t - (6.2 m/s3)t2. What is the average acceleration of the particle between t = 1.0 s and t = 2.0 s (up to two significant figures) ?

  • This Question is Closed
  1. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[Average acceleration=\frac{ Final velocity-initial velocity }{ time 2-time1 }\]

  2. cheska_P
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    The problem I'm having is that I don't know what to do with that long particle function. I tried differentiating it but I think I'm doing it wrong

  3. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Just plug in the first time period to get your initial velocity.

  4. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[2.3+4.1t-6.2t^2\] You can shorten it like this.

  5. cheska_P
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    I figured it out! Thank you. I do have another question though, why is it that the units (m/s, m/s^2, m/s^3) don't matter?

  6. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    It does matter. Better to get it out of the way to get initial and final velocity.

  7. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Are you talking about the final answer? It should be in m/s^2 which is \[m/s^2\]

  8. cheska_P
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    No I was referring to the particle function, you really helped me understand thank you!

  9. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    It actually does

  10. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[m/s+\frac{ m \times s }{ s^2 }+\frac{ m \times s^2 }{ s^3 }=m/s+m/s+m/s\]

  11. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Time is in seconds.

  12. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.