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cheska_P
 one year ago
I'm a visual learning, can some one please work this out so I can see how you get the answer? Physics exam in two days!
The velocity v(t) of a particle as a function of time is given by v(t) = (2.3 m/s) + (4.1 m/s2)t  (6.2 m/s3)t2. What is the average acceleration of the particle between t = 1.0 s and t = 2.0 s (up to two significant figures) ?
cheska_P
 one year ago
I'm a visual learning, can some one please work this out so I can see how you get the answer? Physics exam in two days! The velocity v(t) of a particle as a function of time is given by v(t) = (2.3 m/s) + (4.1 m/s2)t  (6.2 m/s3)t2. What is the average acceleration of the particle between t = 1.0 s and t = 2.0 s (up to two significant figures) ?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[Average acceleration=\frac{ Final velocityinitial velocity }{ time 2time1 }\]

cheska_P
 one year ago
Best ResponseYou've already chosen the best response.1The problem I'm having is that I don't know what to do with that long particle function. I tried differentiating it but I think I'm doing it wrong

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Just plug in the first time period to get your initial velocity.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[2.3+4.1t6.2t^2\] You can shorten it like this.

cheska_P
 one year ago
Best ResponseYou've already chosen the best response.1I figured it out! Thank you. I do have another question though, why is it that the units (m/s, m/s^2, m/s^3) don't matter?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It does matter. Better to get it out of the way to get initial and final velocity.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Are you talking about the final answer? It should be in m/s^2 which is \[m/s^2\]

cheska_P
 one year ago
Best ResponseYou've already chosen the best response.1No I was referring to the particle function, you really helped me understand thank you!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[m/s+\frac{ m \times s }{ s^2 }+\frac{ m \times s^2 }{ s^3 }=m/s+m/s+m/s\]
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