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cheska_P

  • one year ago

The velocity v(t) of a particle as a function of time is given by v(t) = (2.3 m/s) + (4.1 m/s2)t - (6.2 m/s3)t2. What is the average acceleration of the particle between t = 1.0 s and t = 2.0 s (up to two significant figures) ?

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  1. DanJS
    • one year ago
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    differentiate w.r.t. t, and you get acceleration function

  2. cheska_P
    • one year ago
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    I'm not sure what you're telling me to do

  3. DanJS
    • one year ago
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    or without calc you can calculate the slope of a line connecting the endpoints on that v(t) graph over tha interval

  4. DanJS
    • one year ago
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    The average accel is the average rate of change of velocity from t = 1 to t=2, which is just a slope of a line through those two points on v(t)

  5. DanJS
    • one year ago
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    \[\frac{ v(2) - v(1) }{ 2-1 } ~~[m/s^2]\]

  6. cheska_P
    • one year ago
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    ohhh okay I got using what you said about differentiating, the answer would be -14 m/s^2

  7. cheska_P
    • one year ago
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    right?

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