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cheska_P
 one year ago
The velocity v(t) of a particle as a function of time is given by v(t) = (2.3 m/s) + (4.1 m/s2)t  (6.2 m/s3)t2. What is the average acceleration of the particle between t = 1.0 s and t = 2.0 s (up to two significant figures) ?
cheska_P
 one year ago
The velocity v(t) of a particle as a function of time is given by v(t) = (2.3 m/s) + (4.1 m/s2)t  (6.2 m/s3)t2. What is the average acceleration of the particle between t = 1.0 s and t = 2.0 s (up to two significant figures) ?

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DanJS
 one year ago
Best ResponseYou've already chosen the best response.0differentiate w.r.t. t, and you get acceleration function

cheska_P
 one year ago
Best ResponseYou've already chosen the best response.0I'm not sure what you're telling me to do

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0or without calc you can calculate the slope of a line connecting the endpoints on that v(t) graph over tha interval

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0The average accel is the average rate of change of velocity from t = 1 to t=2, which is just a slope of a line through those two points on v(t)

DanJS
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ v(2)  v(1) }{ 21 } ~~[m/s^2]\]

cheska_P
 one year ago
Best ResponseYou've already chosen the best response.0ohhh okay I got using what you said about differentiating, the answer would be 14 m/s^2
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