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anonymous

  • one year ago

PLEASE HELP QUICK WILL FAN AND GIVE A MEDAL Find the exact value of each of the remaining trigonometric functions of θ. sinθ=4/5 , θ in quadrant II

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  1. Nnesha
    • one year ago
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    |dw:1443403087498:dw| sin_is__positive__in_2nd_quadrant sin=opposite/hypotenuse cos=adjacent/hypotenuse tan=opposite/adjacent

  2. Nnesha
    • one year ago
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    sin=opposite/hyp so where_you_should_write_4__and_5_??

  3. Nnesha
    • one year ago
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    which_side_of_right_triangle_is_4?

  4. anonymous
    • one year ago
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    so is 4 the side thats touching the x axis and 5 the hypotenuse? @Nnesha

  5. Nnesha
    • one year ago
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    |dw:1443404056824:dw| side_that_touch_the_angle_is_adjacent

  6. anonymous
    • one year ago
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    oh right sorry thank you!

  7. Nnesha
    • one year ago
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    now_use_the_pytagorean_thorea_to_find_3rd_side

  8. anonymous
    • one year ago
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    so knowing that i just find the rest as usual?

  9. anonymous
    • one year ago
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    3 right?

  10. Nnesha
    • one year ago
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    yes_right_

  11. Nnesha
    • one year ago
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    |dw:1443404178257:dw|

  12. anonymous
    • one year ago
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    so the cosine would be 3?

  13. Nnesha
    • one year ago
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    cos=adjacent/hyp

  14. Nnesha
    • one year ago
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    and just_sin_is_positive_in_2nd_quadrantt_ other_ratios_would_be_NEGATIVE_

  15. Nnesha
    • one year ago
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    BRB

  16. anonymous
    • one year ago
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    so tan would be 4/3 and cot would be 3/4?

  17. Nnesha
    • one year ago
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    right remember the CAST rule |dw:1443406090733:dw|

  18. Nnesha
    • one year ago
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    and we are in 2nd quadrant so tan cos would be negative

  19. Nnesha
    • one year ago
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    \(\color{blue}{\text{Originally Posted by}}\) @faariat so tan would be 4/3 and cot would be 3/4? \(\color{blue}{\text{End of Quote}}\) yes right but since it's in 2nd quadrant so tan is negative and cot neg

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