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Mathematics
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hint: tan(B) = sin(B)/cos(B)
I did that already and am not getting any of the answers provided
If tan B = 9/13 and sin B = 9/13, then cos B = ?

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From @Vocaloid's hint, \[\tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)} \qquad \implies \qquad \cos(\theta) = \frac{\sin(\theta)}{\cos(\theta)} \]
Just plug in your values and solve, simple
whoop, made a typo
\[\cos(\theta) = \frac{\sin(\theta)}{\tan(\theta)}\]
actually I think there's a typo in the question, cos(B) = 1
Using that formula yields me an answers that is not provided
*answer
I've tried every formula today and I don't get any answer that resembles any option OpenStudy was my last resort lol
you're right, it seems theres a typo in the question
weird question i guess we should use logic here LOL \[\rm sin \rm \theta = \frac{ opposite }{ hypotenuse }~~~~ \cos \theta = \frac{ adjacent }{ hypotenuse } ~~\tan \theta = \frac{ opposite }{ adjacent }\] and we know hypotenuse is the longest side of right triangle cos = adjacent /hyp adjacent must be less than hyp|dw:1443408580125:dw|
|dw:1443408594693:dw|
so G looks good
and voc is right there is a typo bec in the explanation tan=9/10 not 13 http://prntscr.com/8la7cy

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