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Albert0898

  • one year ago

Will give a medal. Please explain all steps. http://imgur.com/2COX2YD

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  1. Vocaloid
    • one year ago
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    hint: tan(B) = sin(B)/cos(B)

  2. Albert0898
    • one year ago
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    I did that already and am not getting any of the answers provided

  3. Albert0898
    • one year ago
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    If tan B = 9/13 and sin B = 9/13, then cos B = ?

  4. Jhannybean
    • one year ago
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    From @Vocaloid's hint, \[\tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)} \qquad \implies \qquad \cos(\theta) = \frac{\sin(\theta)}{\cos(\theta)} \]

  5. Jhannybean
    • one year ago
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    Just plug in your values and solve, simple

  6. Jhannybean
    • one year ago
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    whoop, made a typo

  7. Jhannybean
    • one year ago
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    \[\cos(\theta) = \frac{\sin(\theta)}{\tan(\theta)}\]

  8. Vocaloid
    • one year ago
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    actually I think there's a typo in the question, cos(B) = 1

  9. Albert0898
    • one year ago
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    Using that formula yields me an answers that is not provided

  10. Albert0898
    • one year ago
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    *answer

  11. Albert0898
    • one year ago
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    I've tried every formula today and I don't get any answer that resembles any option OpenStudy was my last resort lol

  12. Vocaloid
    • one year ago
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    you're right, it seems theres a typo in the question

  13. Nnesha
    • one year ago
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    weird question i guess we should use logic here LOL \[\rm sin \rm \theta = \frac{ opposite }{ hypotenuse }~~~~ \cos \theta = \frac{ adjacent }{ hypotenuse } ~~\tan \theta = \frac{ opposite }{ adjacent }\] and we know hypotenuse is the longest side of right triangle cos = adjacent /hyp adjacent must be less than hyp|dw:1443408580125:dw|

  14. Nnesha
    • one year ago
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    |dw:1443408594693:dw|

  15. Nnesha
    • one year ago
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    so G looks good

  16. Nnesha
    • one year ago
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    and voc is right there is a typo bec in the explanation tan=9/10 not 13 http://prntscr.com/8la7cy

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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