## Albert0898 one year ago Will give a medal. Please explain all steps. http://imgur.com/2COX2YD

1. Vocaloid

hint: tan(B) = sin(B)/cos(B)

2. Albert0898

I did that already and am not getting any of the answers provided

3. Albert0898

If tan B = 9/13 and sin B = 9/13, then cos B = ?

4. Jhannybean

From @Vocaloid's hint, $\tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)} \qquad \implies \qquad \cos(\theta) = \frac{\sin(\theta)}{\cos(\theta)}$

5. Jhannybean

Just plug in your values and solve, simple

6. Jhannybean

7. Jhannybean

$\cos(\theta) = \frac{\sin(\theta)}{\tan(\theta)}$

8. Vocaloid

actually I think there's a typo in the question, cos(B) = 1

9. Albert0898

Using that formula yields me an answers that is not provided

10. Albert0898

11. Albert0898

I've tried every formula today and I don't get any answer that resembles any option OpenStudy was my last resort lol

12. Vocaloid

you're right, it seems theres a typo in the question

13. Nnesha

weird question i guess we should use logic here LOL $\rm sin \rm \theta = \frac{ opposite }{ hypotenuse }~~~~ \cos \theta = \frac{ adjacent }{ hypotenuse } ~~\tan \theta = \frac{ opposite }{ adjacent }$ and we know hypotenuse is the longest side of right triangle cos = adjacent /hyp adjacent must be less than hyp|dw:1443408580125:dw|

14. Nnesha

|dw:1443408594693:dw|

15. Nnesha

so G looks good

16. Nnesha

and voc is right there is a typo bec in the explanation tan=9/10 not 13 http://prntscr.com/8la7cy