Im having massive brain block. -exp(t) + 3exp(t/2) = 0, solve for t

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Im having massive brain block. -exp(t) + 3exp(t/2) = 0, solve for t

Mathematics
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replace \(\frac{t}{2}\) by \(x\) and solve \[-e^{2x}+3e^x=0\]
you move one term to the other side and take natural log of both sides?
solve as a quadratic equation

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Other answers:

factor out an \(e^x\)
\[-e^x(e^x-3)=0\]
exp(x) = 3 or 0 but never gets to 0
right
make sure to replace \(x\) by \(\frac{t}{2}\)
ok, thank you very much!
yw

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