9.55 x 10^24 molecules of CH3OH is how many grams?

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

9.55 x 10^24 molecules of CH3OH is how many grams?

Chemistry
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

use avogadro's number: \(\sf \color{red}{6.022 \times 10^{22}\frac{mole}{molecule}}\)
sorry, 23rd power, not 22.
^he's right. \(\sf moles=\dfrac{molecules}{Avogadro's~number}\)

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Thank you!
It's not \(6.022*10^{23} \dfrac{\text{mole}}{\text{molecule}}\)! It is \(6.022*10^{23}\dfrac{\text{}}{\text{mole}}\); in this case the constituent particle is a molecule. \[1 \text{ mole} * 6.022*10^{23}\dfrac{\text{molecule}}{\text{mole}} = 1 \cancel{\text{ mole}} * 6.022*10^{23}\dfrac{\text{molecule}}{\cancel{\text{mole}}}\]\[=6.022*10^{23}\text{ molecule}\] Make a point of using the units correctly in all of your work and they will help you find or prevent many errors, especially in problems containing unit conversions.

Not the answer you are looking for?

Search for more explanations.

Ask your own question