## anonymous one year ago 9.55 x 10^24 molecules of CH3OH is how many grams?

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1. anonymous

use avogadro's number: $$\sf \color{red}{6.022 \times 10^{22}\frac{mole}{molecule}}$$

2. anonymous

sorry, 23rd power, not 22.

3. aaronq

^he's right. $$\sf moles=\dfrac{molecules}{Avogadro's~number}$$

4. anonymous

Thank you!

5. whpalmer4

It's not $$6.022*10^{23} \dfrac{\text{mole}}{\text{molecule}}$$! It is $$6.022*10^{23}\dfrac{\text{<constituent particle>}}{\text{mole}}$$; in this case the constituent particle is a molecule. $1 \text{ mole} * 6.022*10^{23}\dfrac{\text{molecule}}{\text{mole}} = 1 \cancel{\text{ mole}} * 6.022*10^{23}\dfrac{\text{molecule}}{\cancel{\text{mole}}}$$=6.022*10^{23}\text{ molecule}$ Make a point of using the units correctly in all of your work and they will help you find or prevent many errors, especially in problems containing unit conversions.