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Meehan98

  • one year ago

I need help with Pre-Calculus, please!

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  1. Meehan98
    • one year ago
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    Solve for the missing side or angle.|dw:1443406044841:dw|

  2. anonymous
    • one year ago
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    is it a right angled triangle?

  3. Meehan98
    • one year ago
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    I apologize for the poor drawing. I know that I use tangent so it would be: tan(theta)=.5952 but I don't know how to get degrees after that.

  4. Meehan98
    • one year ago
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    Yes, it's a right triangle.

  5. Jhannybean
    • one year ago
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    SOHCAHTOA you have an opposite side to that angle and an adjacent one. The ratio you need to use is `TOA` = \(\tan(\theta) = \dfrac{17.5}{29.4}\)

  6. Jhannybean
    • one year ago
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    So naturally to find the missing angle we take the arctan function. \[\theta = \tan^{-1}\left(\frac{17.5}{29.4}\right)\]

  7. anonymous
    • one year ago
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    \[\tan \theta=\frac{ 17.5 }{ 29.4 },\theta=\tan^{-1} \frac{ 17.5 }{ 29.4 }=30.76~ degree\]

  8. Meehan98
    • one year ago
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    Oh! Thank you to both of you!!

  9. anonymous
    • one year ago
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    yw

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