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marco26
 one year ago
10. The sides of the triangle are 40 cm, 50 cm, and 60 cm. How far is the point of intersection of the perpendicular bisector of the sides of the triangle to any of its vertex?
marco26
 one year ago
10. The sides of the triangle are 40 cm, 50 cm, and 60 cm. How far is the point of intersection of the perpendicular bisector of the sides of the triangle to any of its vertex?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it is radius of circumcircle. \[R=\frac{ abc }{ 4~ area~ of~ \triangle }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0area of triangle\[=\sqrt{s \left( sa \right)\left( sb \right)\left( sc \right)}\] where a,b,c are sides of triangle. and 2s=a+b+c

marco26
 one year ago
Best ResponseYou've already chosen the best response.0ok thanks, I get it now :)
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