sbuck98
  • sbuck98
can someone help me with this?
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Astrophysics
  • Astrophysics
Please limit one question per post
Astrophysics
  • Astrophysics
So solve for L \[V = LWH\] try dividing both sides WH what happens?

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sbuck98
  • sbuck98
I have no idea, can you work through all of these with me? I'll repost each 3 pages and give u a medal for each. @astrophysis
Vocaloid
  • Vocaloid
|dw:1443410795231:dw|
Vocaloid
  • Vocaloid
any thoughts?
Vocaloid
  • Vocaloid
does this make things more clear??|dw:1443411170938:dw|
Astrophysics
  • Astrophysics
|dw:1443411173529:dw| notice that turns into 1
sbuck98
  • sbuck98
so it's 1?
alesia/bailey
  • alesia/bailey
lol, basically you are trying to isolate the letter your trying to find. so because is sais V=LWH the LWH means multiplying and you have to do the opposite of multiplying and so you divide. when you divide LWH with WH you are cancelling them on one side, they cancel each other out. but what ever you do one one side, you do to the other. so if you divide on one side, you divide the other side. and when you divide LWH with WH to cancel those you then have L isolated. but you have to divide WH with V because you do it on both sides. so you get V divided by WH equals L V/WH=L you see that L is all by itself. that's how you solve the problem, if this makes any sense.
alesia/bailey
  • alesia/bailey
2x+3y=4 you're trying to get y by itself 2x+3y=4 -2x -2x 3y=4-2x 3 times y, to cancel these out you have to do the opposite of multiplying and you divide. divide the 3 on both sides so why is by itself 3y/3=4-2x y=4-2x/3 or y=4-2x/3
alesia/bailey
  • alesia/bailey
and the other two, the way to do it is to look for keywords like IS means =, plus means + or PRODUCT OF A NUMBER means a variable like X and means +, less than means subtract. you just have to find out what its asking for and usually underlining the important words that give you the equation.

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