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  • one year ago

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  1. anonymous
    • one year ago
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    Do the inside function first. What do you get when you plug in 1 for x in g(x)?

  2. anonymous
    • one year ago
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    yeah. Now do the outside function. Plug in -1 for x in f(x)

  3. anonymous
    • one year ago
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    As you have it typed, that's right, but I assume the 2 is supposed to be an exponent. \(x^2=x*x\) Use the ^ symbol in the future \[f(-1)=(-1)^2+3(-1)+6\] \[=(-1)(-1)+3(-1)+6\]

  4. anonymous
    • one year ago
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    What's confusing you? the only thing you did wrong was the arithmetic when you plugged in. I put up a correction above

  5. anonymous
    • one year ago
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    put what I typed above into a calculator

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