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Ninth mein hai ya tenth mein?

9th me

Thus the answer is -1.

Yes..

Exams..

Is that it? o_O

\[x -k = \frac{3x^3 - 2x^2 - 7x - 2}{(x-2)(3x+1)} = \frac{3x^3 - 2x^2 - 7x - 2}{3x^2 - 5x - 2}\]

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\[x-k = x+1\]\[k = -1\]

Okay....I get it...give me a min..

All right I got it. Thanks a bunch. c:

Ussey samajh aaya?

Ab samjhaunga na usko c:

So 3 se multiply kiya taaki fraction me na rahe, right?

*Manmohan Singh shtyle*
Theek hai?

Haha

Ok, just to be sure.
Suppose 2x+1 is a factor of \(\sf 2x^2-x-1\) then other zero will be +1 ?

Yes.

Ok, thanks again..

Badiya.