A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • one year ago

The velocity of an object increases from –10 m/s to –15 m/s in 2.0 s. What is the average acceleration of the object? +2.5 m/s2 –2.5 m/s2 +12.5 m/s2 –12.5 m/s2

  • This Question is Closed
  1. Rushwr
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    \[Acceleration = \frac{ \Delta V }{ \Delta t }\]

  2. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    WHAT DOES THAT MEAN?

  3. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    v divided by t?

  4. Rushwr
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    delta V = final velocity - initial velocity Delta T = time difference.

  5. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    O.O

  6. Rushwr
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Did u get it ? Substitute and get the answer !!!

  7. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I dont understand anything

  8. Rushwr
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Do u understand the question ?

  9. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    no

  10. Rushwr
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Haven't u learned this lesson at school ?

  11. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I go to online school and its harder to understand

  12. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    q.q

  13. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @TorilovesVampires

  14. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @countonme123

  15. Rushwr
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    okai Acceleration is the rate of change of velocity. Velocity is the rate of change of speed. We do have equations for acceleration. But if we are asked to find the average acceleration then we use only the below equation \[Average acceleration = \frac{ Final velocity - initial velocity }{ time difference}\]

  16. Rushwr
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Here the final velocity is -15ms^-1 Initial velocity is -10ms^-1 and the time difference is 2s now substitute and see

  17. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    how would I do that?

  18. Rushwr
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    \[Acceleration = \frac{ -15 - (-10) }{ 2 } = \frac{ -5 }{ 2 } = -2.5ms ^{-1}\]

  19. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thnk u

  20. Rushwr
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    no probleem.

  21. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.