## anonymous one year ago The velocity of an object increases from –10 m/s to –15 m/s in 2.0 s. What is the average acceleration of the object? +2.5 m/s2 –2.5 m/s2 +12.5 m/s2 –12.5 m/s2

1. Rushwr

$Acceleration = \frac{ \Delta V }{ \Delta t }$

2. anonymous

WHAT DOES THAT MEAN?

3. anonymous

v divided by t?

4. Rushwr

delta V = final velocity - initial velocity Delta T = time difference.

5. anonymous

O.O

6. Rushwr

Did u get it ? Substitute and get the answer !!!

7. anonymous

I dont understand anything

8. Rushwr

Do u understand the question ?

9. anonymous

no

10. Rushwr

Haven't u learned this lesson at school ?

11. anonymous

I go to online school and its harder to understand

12. anonymous

q.q

13. anonymous

@TorilovesVampires

14. anonymous

@countonme123

15. Rushwr

okai Acceleration is the rate of change of velocity. Velocity is the rate of change of speed. We do have equations for acceleration. But if we are asked to find the average acceleration then we use only the below equation $Average acceleration = \frac{ Final velocity - initial velocity }{ time difference}$

16. Rushwr

Here the final velocity is -15ms^-1 Initial velocity is -10ms^-1 and the time difference is 2s now substitute and see

17. anonymous

how would I do that?

18. Rushwr

$Acceleration = \frac{ -15 - (-10) }{ 2 } = \frac{ -5 }{ 2 } = -2.5ms ^{-1}$

19. anonymous

thnk u

20. Rushwr

no probleem.