anonymous
  • anonymous
The velocity of an object increases from –10 m/s to –15 m/s in 2.0 s. What is the average acceleration of the object? +2.5 m/s2 –2.5 m/s2 +12.5 m/s2 –12.5 m/s2
Mathematics
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anonymous
  • anonymous
The velocity of an object increases from –10 m/s to –15 m/s in 2.0 s. What is the average acceleration of the object? +2.5 m/s2 –2.5 m/s2 +12.5 m/s2 –12.5 m/s2
Mathematics
jamiebookeater
  • jamiebookeater
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Rushwr
  • Rushwr
\[Acceleration = \frac{ \Delta V }{ \Delta t }\]
anonymous
  • anonymous
WHAT DOES THAT MEAN?
anonymous
  • anonymous
v divided by t?

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Rushwr
  • Rushwr
delta V = final velocity - initial velocity Delta T = time difference.
anonymous
  • anonymous
O.O
Rushwr
  • Rushwr
Did u get it ? Substitute and get the answer !!!
anonymous
  • anonymous
I dont understand anything
Rushwr
  • Rushwr
Do u understand the question ?
anonymous
  • anonymous
no
Rushwr
  • Rushwr
Haven't u learned this lesson at school ?
anonymous
  • anonymous
I go to online school and its harder to understand
anonymous
  • anonymous
q.q
anonymous
  • anonymous
anonymous
  • anonymous
Rushwr
  • Rushwr
okai Acceleration is the rate of change of velocity. Velocity is the rate of change of speed. We do have equations for acceleration. But if we are asked to find the average acceleration then we use only the below equation \[Average acceleration = \frac{ Final velocity - initial velocity }{ time difference}\]
Rushwr
  • Rushwr
Here the final velocity is -15ms^-1 Initial velocity is -10ms^-1 and the time difference is 2s now substitute and see
anonymous
  • anonymous
how would I do that?
Rushwr
  • Rushwr
\[Acceleration = \frac{ -15 - (-10) }{ 2 } = \frac{ -5 }{ 2 } = -2.5ms ^{-1}\]
anonymous
  • anonymous
thnk u
Rushwr
  • Rushwr
no probleem.

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