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A) (-2,4)
B) (-2,3)
C) (-3,3)
D) (-3,4)

anone wanna assist me please? i wanna learn how to do this myself :(

that formula you have typed out, do you know what it's for?

if you say triangle ABC congruent to DEF
it means
AB=DE
BC=EF
AC=DF

with me so far?

yes :)

yeah, exactly

find the lengths EF and DF for each of the options, compare with the lengths AC and BC

but how will i know it is right?

*c

so i go all around? ok so first i find EF=AC right?

ok let me find AC and BC first

\[AC = \sqrt{(1-2)^2 + (-1-3)^2}\]

\[BC = \sqrt{(-1-2)^2 + (2-3)^2}\]

umm... how did you get A=(1,-1) ??

i looked at the graph to see where the point is, did i saw it wrong? omg let me see haha

is it (1,0)?

yep :)

so if you want to find the length AC
then think of A =(x1,y1) and C=(x2,y2)

so, x1=1 and y1=0
x2=2 and y2=3

ohhhhhh kk hha now ill find AC

i got 10 for AC

lol i wanna make sure

i have a feeling i am doing it wrong

or is everything supoosed to stay in the sqr root ?

so its supposed to be the sqr root of 10?

so2 is my answer?

yep, AC is square root of 10.

so then i find BC?

not necessary, option 2 is the only one which gives you EF= square root of 10

did you try finding EF for all the options?

what do you mean?

i'm sorry i meant DF

we established that for the two triangles to be congruent,
length AC = length DF

what do you mean "so i can test B' ?

option b for F

oh..lol. Yep, you are absolutely right then

yay! lol

kk ima test it

alright

yup