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anonymous
 one year ago
please help me with this question! Using the completingthesquare method, rewrite f(x) = x2 − 8x + 3 in vertex form. f(x) = (x − 8)2 f(x) = (x − 4)2 − 13 f(x) = (x − 4)2 + 3 f(x) = (x − 4)2 + 16
anonymous
 one year ago
please help me with this question! Using the completingthesquare method, rewrite f(x) = x2 − 8x + 3 in vertex form. f(x) = (x − 8)2 f(x) = (x − 4)2 − 13 f(x) = (x − 4)2 + 3 f(x) = (x − 4)2 + 16

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The question is Using the completingthesquare method, rewrite f(x) = x2 − 8x + 3 in vertex form.

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1do you have to show your work or can you just do it?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you don't have to show your work

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1ok then lets to it quick you have \[f(x)=x^28x+3\] right?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1so go right to \[f(x)=(x4)^2+k\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1to find \(k\) plug in 4 in to \[f(x)=x^28x+3\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so I solve f(x)= (x4)^2 +k and for k, I plug in 4?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1yes, let me know what you get and i will check it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay I'll solve it real quick :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I squared the 4 in the parenthesis and got f(x)= (x16)+4

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is that all that I have to do?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1lets back up a second

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1we got half of 8 is 4, so it s going to look like \[f(x)=(x4)^2+k\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1now we need the number \(k\) right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes and you said to plug 4 in for k right?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1to find \(k\) start with \[f(x)=x^28x+3\] and find \(f(4)\) \[f(4)=4^28\times 4+3\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1let me know what you get now

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh! okay. I totally switched up what you said :o I'll resolve it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I got 13 on my calculator, but when I solved it on paper I got 35. Sorry if I'm annoying you, I just don't understand algebra 2 at all :/

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1it is ok dear, not problem the correct one is \(13\) lets do it with pencil and paper

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1\[f(4)=4^28\times 4+3\] first square \[168\times 4+3\] then multiply \[1632+3\] then subtract \[16+3\] then add \[13\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1final answer to your question "vertex form" is \[f(x)=(x4)^213\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh! I solved the exponent first and then subtracted. But thank you so much for helping me! :)

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1\[\color\magenta\heartsuit\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Hey @misty1212 . Can you help me with one more question? It also involves the vertex form and standard form

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It's this  Rewrite f(x) = –2(x − 3)2 + 2 from vertex form to standard form.

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1ok this one is going the other way around from vertex to standard how is your algebra?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1because that is what you need \[2(x3)^2+2=2(x3)(x3)+2\] you have to multiply out, distribute, combine like terms

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Should I solve that and then tell you what I got?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1sure don't forgot to multiply out first \[(x3)(x3)\] requires 4 multiplications then multiply each term by \(2\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So for the first part of the equation, I got 2x+6^2 +2. Is that right so far?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1\(3\times (3)=+9\) lets go slow

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1\[(x3)(x3)\]first we get \[x^23x3x+9\] let me know when that is clear, or if not, ask

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes that makes sense

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1you see where each term came from?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1some times math teachers call it "foil"

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yeah. The x's get multiplied to each other and that makes x^2, and then you multiply the 3's to the x's and get 3x3x. Last, you multiply the 3's to each other and you get 9. But how would we put that into standard form?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0My answers are f(x) = –2x2 − 18 f(x) = –2x2 + 12x + 20 f(x) = –2x2 + 12x − 16 f(x) = 4x2 − 24x + 38

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1ok so we are at \[x^23x3x+9\] which is the same as \[x^26x+9\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1then \[2(x^26x+9)=2x^2+12x18\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1then add the \(2\) at the end, get \[x^2+12x16\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So the answer would be f(x)= 2x^2+12x16?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes. Do you do FLVS?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1lol no dear, i don't

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1good luck with the algebra \[\color\magenta\heartsuit\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you so much! And thanks for the help again :)
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