anonymous
  • anonymous
How many moles of CaO form when 98.60 g CaCO3 decompose
Chemistry
schrodinger
  • schrodinger
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Rushwr
  • Rushwr
\[CaCO _{3} ---> CaO + CO _{2}\] as we can see the no. of moles of CacO3 = no. of moles of CaO so it's just the matter of finding the no. of moles of CaCO3 right? we know no. of moles = mass divided by the molar mass Molar mass of CaCO3 = 100gmol^-1 \[moles = \frac{ 93.5g }{ 100gmol ^{-1} } = 0.935g\]

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