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some.random.cool.kid
 one year ago
Solve the equation 4x2 − 12x + 3 = 0 by completing the square. Verify your answer using the quadratic formula.
some.random.cool.kid
 one year ago
Solve the equation 4x2 − 12x + 3 = 0 by completing the square. Verify your answer using the quadratic formula.

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some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0@nincompoop

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0i have a few of these this is just the first that i need help with...

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0@ParthKohli

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0@whpalmer4

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0ik the forumla is this: x = [ b ± sqrt(b^2  4ac) ] / 2a

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0well we should use complete the square method you can move the constant term to the right side

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0x is the term correct?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0\[ \huge\rm 4x^2 − 12x + 3 = 0\] subtract 3 both sides

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0not just x term are divided by plus or negative sign

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0uh... subtract the 4x^2 by 3 and the 12 by 3?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0\[\huge\rm Ax^2+Bx+C=0\]quadratic e quation where A=leading coefficient B=middle term C=constant term(number with no variable )

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443453772906:dw you can't combine 3 and 4x^2 they arn't like terms

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0im not sure what you do next after you get 3..

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443453908051:dw we should complete the square of the left part

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0\[\huge\rm \color{Red}{4x^2+12x}=3\] what is the common factor at left side ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0no just take out the common number not the varaible

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0uh ... im confused. am i supposed to take out the 4 and 12 and divide them?

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0besides the x i see nothing in common...

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0well it's 4x^2+12x so we just need to take out the common number

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0what are the factors of 4 and 12 ?

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.01, 2, 4 ... 4 is best factor... then i divide both by four to get 3 right?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0you need GREATEST COMMON FACTOR 1,2,4 are factors of 4 1,2,3,4,6,12 are factors of 12 so which number is common ?

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0uh i said 4...

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0is there one greater than thta?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0i don't understand what u mean "divide `both` to get 3"

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0\[\huge\rm 4(x^2+3x)=3\]when you take out 4 from 4 u will get 1

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0you still have the 12x

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0i was saying didvide the 4x^2 and 12x by the common factor to simplify the solution.

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0now we can complete the square of (x^2+3x) we should divide b by b here is an example \[\huge\rm a(x^2+bx)=C\] divide b by 2 \[\huge\rm a(x+\frac{ b }{ 2 })^2=C + (\frac{ b }{ 2})^2 \] and then add(b/2)^2 to both sides

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0yes right. i read it wrong. so sorry

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0\[\huge\rm 4(x^2+3x)=3\] take half of the x term and then square it add square to the both sides

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0you have to x's which one do i take half of?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0first one is x^2 2nd one is x

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0so take half of the second one?

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0uh... ok so now you'll have x+ 3?

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0thats not a negative sign

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0x+3 how ? we should take half of 3 in other words just divide `b by 2`

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0how am i dividing 3x by 2?

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0/i thought you wanted me to take away x on both sides..

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0here is an example \[\huge\rm a(x^2+bx)=C\] divide b by 2 \[\huge\rm a(x+\frac{ b }{ 2 })^2=C + (\frac{ b }{ 2})^2 \times a \] and then add(b/2)^2 to both sides here is an example

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0well first we need to divide b by 2 take square of (b/2)^2 then add (b/2)^2 to both sides

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0what is b in ur equation ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.03 =b not 3x x is variable

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0yes right \[\huge\rm 4(x^2+\color{blue}{\frac{ 3x }{ 2 }}+\color{Red}{(\frac{ 3 }{ 2 })^2}) = 3 +\color{red}{(\frac{3}{2})^2 } \times 4\] look at the blue term i took half of 3 and then add (b/2)^2 to both sides and sicne we got the common factor we should multiply (b/2)^2 by 4 at right side

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0do we get rid of negative 3 with the positive 3

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0positive 3 ?? it's 3x you can't combine 3x with 3 they are not like terms

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0then your left with whats in blue right?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0right we can factor this quadraticc equation (x^2 +3/2x + (3/2)^2) or look at this example \[\huge\rm (x^2+bx) =(x+\frac{ b }{ 2 })^2\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0you need to convert left side in squared form

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0so its a bit of a leap here but i believe the simplified form would be 3 + 2\[\sqrt{6}\] over 2?

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0everything over 2*

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0and how did you get that ?

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0well you told me that like terms cant combine

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0leaving negative 3 alone.

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0look at this example \[\huge\rm (x^2+bx) =(x+\frac{ b }{ 2 })^2\] and tell me how would you write \[(x^2+3x) = ????\]

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0then you said something about b being divided by2? which i believe gave me that..

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0how did you write \[(x^2+3x)\] in squared form ?

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.03x^2? idk

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0ik your left with one x right?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0\(\color{blue}{\text{Originally Posted by}}\) @Nnesha look at this example \[\huge\rm (x^2+bx) =(x+\frac{ b }{ 2 })^2\] and tell me how would you write \[(x^2+3x) = ????\] \(\color{blue}{\text{End of Quote}}\)

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0thats where im lost though...

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0yea that's obvious we have to solve for x

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0then how you got the final x value ?

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0i got what?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0here is another example \[(x^2+6x)=(x+\frac{ 6 }{ 2})^2=(x+3)^2\]

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0wait but isn't that similar to what i had?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0\[\huge\rm 4(x^2+\color{blue}{\frac{ 3x }{ 2 }}+\color{Red}{(\frac{ 3 }{ 2 })^2}) = 3 +\color{red}{(\frac{3}{2})^2 } \times 4\] \[4(x+\frac{ 3 }{ 2})^2=3+(\frac{ 3 }{ 2 })^2 \times 4\] according to what i said (x^2+bx)=(x+b/2)^2

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0solve this to get the answer \[4(x+\frac{ 3 }{ 2})^2=3+(\frac{ 3 }{ 2 })^2 \times 4\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0here is how we can write in squared form \[(x^2+bx)=(x+\frac{ b }{ 2 })^2\] \[(x^2+6x)=x^2+6x+\color{reD}{9}\] i divided 6 by 2 which is equal to 3 then squared 3 that's how i got 9 now we can factor x^2+6x+9 (x+3)(x+3) are factors of that quadratic equation which is same as (x+3)^2 so in short we can do this \[(x^2+bx)=(x+\frac{ b }{ 2})^2\]\[(x^2+6x)=(x+\frac{ 6 }{ 2 })^2=(x+3)^2\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0feel free to ask question about that^let me know if you have question on that

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0ok thank you

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0i had another one mind helping?

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0i believe i did

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0Solve x2 − 5x + 1 = 0 using the quadratic formula.

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0i know the first step to this ...

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0can u make a new post bec this one is laggy

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0i have noticed

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0ye it keeps moving hard to use latex on this post
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