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anonymous

  • one year ago

Trapezoid ABCD is reflected over the line y = x. What rule shows the input and output of the reflection, and what is the new coordinate of A'?

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  1. anonymous
    • one year ago
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    (x,y)→(y,-x); A' is at (1, 5) (x,y)→(y,x); A' is at (1, -5) (x,y)→(-x,y); A' is at (5, 1) (x,y)→(-x,-y); A' is at (5, -1)

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  2. anonymous
    • one year ago
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    @mathmate

  3. mathmate
    • one year ago
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    It is always a good idea to retrace the transformations. The question states that A has undergone the transoformation (x,y)->(y,-x) which results in (1,5) We need to do the inverse transformation, namely find (x,y). From the above, y=1 and -x=5 which means that x=-5, y=1, A(-5,1) Now you need to choose the transformation of reflection about y=x. Hints: \(S_{y=x}: (x,y) -> (y,x)\) ..........reflection about y=x \(S_{y=-x}: (x,y) -> (-y,-x)\).........reflection about y=-x

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