anonymous
  • anonymous
Given the following balanced reaction of hydrochloric acid and oxygen gas forming chlorine gas and water, how many grams of hydrochloric acid will be needed to form 335 grams of chlorine gas, assuming there is excess oxygen present? (To find the molar mass in the problem, use the periodic table and round the mass to the hundreds place for calculation.) 4HCl(aq) + O2 ---> 2Cl2(g) + 2H2O(l)
Chemistry
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Photon336
  • Photon336
@Darkhawke first of all is that reaction balanced? and if so how do you know?
Rushwr
  • Rushwr
@Darkhawke Please carry on with photon. Answer him.
anonymous
  • anonymous
Yes, the equation is balanced. However, I am unsure of how to solve this question.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Well, you can tell if it's balanced by checking if you have the same number of atoms in the product and result. Here, you'll see that both sides have 2 oxygen, 4 chlorine, and 4 hydrogen.
anonymous
  • anonymous
To answer your main question, you'll need to use molar mass and some basic stoichemistry to get your answer. I highly advise learning this skill yourself, as it will come in handy many times.

Looking for something else?

Not the answer you are looking for? Search for more explanations.