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some.random.cool.kid
 one year ago
Solve x2 − 5x + 1 = 0 using the quadratic formula.
some.random.cool.kid
 one year ago
Solve x2 − 5x + 1 = 0 using the quadratic formula.

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some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0step one is to 1 by both sides?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1now just use the quadraitc formula

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1you already know the formula so just plugin a ,b ,c values

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0yeah but first 1 to the 1 and 0 go first dont they i have to simplify them.

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.0comparing your equation with the general quadratic equation: \[a{x^2} + bx + c = 0\] we get: a=1, b=5, and c=1 now, please apply this formula: \[x = \frac{{  b \pm \sqrt {{b^2}  4 \times a \times c} }}{{2 \times a}}\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1no quadratic equation should be in standard form \[\huge\rm Ax^2+Bx+C=0\] equal to zero

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1that was for completing the square method but when we use quadratic formula we ned `standard form`

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0so what is the standard is it like ... idk actually

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\(\color{blue}{\text{Originally Posted by}}\) @Nnesha no quadratic equation should be in standard form \[\huge\rm Ax^2+Bx+C=0\] equal to zero \(\color{blue}{\text{End of Quote}}\) ^^that's the standard form

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1where a=leading coefficient b=middle term c=constant term

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1now just plugin a ,b, c values into the quadratic formula

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0writing all these down just in case your wondering... very helpful info for big exam EOC..

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1that's Awesome take ur time write theses down and practice as much as u can

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0k so what do i next because i wasn't sure...

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1did you substitute a ,b c for their values ?

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0a is x^2 right ?

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0and b is 5x?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1no just the coefficient not the variable

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1look at the Michele'z comment a=1 bec x^2 is same as 1x^2

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0so 5 since its not a variable?

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0/so your saying 1^2? i dont get how thats possible...

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1there is invisible one at front of x^2 x^2 is same as 1x^2 so leading coefficient is one

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1i'm not saying x =1 leading coefficient is one

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\[\huge\rm \color{red}{1}x^2+\color{blue}{5}x+\color{green}{1}=0\] \[\huge\rm \color{ReD}{A}x^2+\color{blue}{B}x+\color{green}{C}=0\]

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0k thanks i gtg thanks for your help. :D
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