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KJ4UTS

  • one year ago

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  1. KJ4UTS
    • one year ago
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  2. KJ4UTS
    • one year ago
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    I think the answer is the one I have marked but I am not sure?

  3. timinthor
    • one year ago
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    yes, you are correct:)

  4. anonymous
    • one year ago
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    I might be wrong here, but the last one should be the answer. Just going by the quadratic formula, the denominator should contain 2(a) and a=2 in this scenario, so the denominator would be 4

  5. timinthor
    • one year ago
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    please medal if correct, thanks

  6. KJ4UTS
    • one year ago
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    could you explain why i am not sue how to get this?

  7. anonymous
    • one year ago
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    Do you know the quadratic formula?

  8. KJ4UTS
    • one year ago
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    yes

  9. anonymous
    • one year ago
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    Okay, so the first step here is to add the 3 to the other side

  10. anonymous
    • one year ago
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    Then you've got your polynomial. You'll need to plug the polynomial's numbers into the quadratic formula. Let me know what you get when you do that.Don't solve it just yet, only show what you did when you plugged them in

  11. KJ4UTS
    • one year ago
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    -6+-√-6^2-4(2)(3) / 2(2) ?

  12. anonymous
    • one year ago
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    Very close. You just accidentally switched the sign for your 6^2

  13. anonymous
    • one year ago
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    the b^2 is positive(unless b in the polynomial is negative)

  14. KJ4UTS
    • one year ago
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    I see

  15. anonymous
    • one year ago
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    So, now you've got the equation. What's next?

  16. KJ4UTS
    • one year ago
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    plug it in and solve? 2(2) would be 4 i guess like you said

  17. anonymous
    • one year ago
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    It would be. That's the shortcut to your answer for this question in particular. Do you want to solve the rest just for your own sake or do you have it?

  18. KJ4UTS
    • one year ago
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    oh so it would be the last one? i was getting √3 - 3/2 for some reason

  19. anonymous
    • one year ago
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    Did you maybe forget that the bottom was 2a? Only reason I remember that is because my Algebra 1 teacher a few years ago told us a story for the formula

  20. KJ4UTS
    • one year ago
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    ok would you mind checking this one for me

  21. KJ4UTS
    • one year ago
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    I got the last one but I am not sure if its right either

  22. anonymous
    • one year ago
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    Those are the ones I was never sure of haha. You might be able to use an online calculator and see if it actually passes through when you plug in each equation. I'm not positive on it

  23. KJ4UTS
    • one year ago
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    ok thank you :)

  24. KJ4UTS
    • one year ago
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    I figured it out just plug in x which is 4 and you get -1 so my equation works :)

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