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anonymous
 one year ago
5 combination 2
anonymous
 one year ago
5 combination 2

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Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2dw:1443467122442:dw like this

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2if yes then use the formula \[\huge\rm ^nC_r= \frac{ n! }{ r!(nr)! }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 5! }{ 2! (52)! }=\frac{ 1*2*3*4*5 }{ 1*2(3)! }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 120 }{ 6! }\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2you can't multiply 2 with 3! 3! is 3 times 2 times1 so 1 times 2 (3 times 2)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2\[2(3)!=2(3 \times 2 \times 1)\]

phi
 one year ago
Best ResponseYou've already chosen the best response.0btw, it is better to do it this way: \[ \frac{5\cdot 4 \cdot 3!}{2 \cdot 3!} \] notice that the 3! cancels, you have have 5* 4/2 = 5*2 =10 this way you don't have to calculate huge numbers.
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