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anonymous

  • one year ago

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  1. Nnesha
    • one year ago
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    |dw:1443467122442:dw| like this

  2. Nnesha
    • one year ago
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    ?

  3. Nnesha
    • one year ago
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    if yes then use the formula \[\huge\rm ^nC_r= \frac{ n! }{ r!(n-r)! }\]

  4. anonymous
    • one year ago
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    k one sec

  5. anonymous
    • one year ago
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    \[\frac{ 5! }{ 2! (5-2)! }=\frac{ 1*2*3*4*5 }{ 1*2(3)! }\]

  6. Nnesha
    • one year ago
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    looks good

  7. anonymous
    • one year ago
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    \[\frac{ 120 }{ 6! }\]

  8. Nnesha
    • one year ago
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    how did you get 6! ?

  9. Nnesha
    • one year ago
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    you can't multiply 2 with 3! 3! is 3 times 2 times1 so 1 times 2 (3 times 2)

  10. anonymous
    • one year ago
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    1*2(3)!

  11. Nnesha
    • one year ago
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    \[2(3)!=2(3 \times 2 \times 1)\]

  12. anonymous
    • one year ago
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    so 120/12

  13. anonymous
    • one year ago
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    =10

  14. Nnesha
    • one year ago
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    right

  15. anonymous
    • one year ago
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    thx

  16. Nnesha
    • one year ago
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    np,good work!

  17. phi
    • one year ago
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    btw, it is better to do it this way: \[ \frac{5\cdot 4 \cdot 3!}{2 \cdot 3!} \] notice that the 3! cancels, you have have 5* 4/2 = 5*2 =10 this way you don't have to calculate huge numbers.

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