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anonymous
 one year ago
How do I solve this integral using a) the midpoint rule and b) simp son's rule to approximate the integral? can you please explain? thank you!!
anonymous
 one year ago
How do I solve this integral using a) the midpoint rule and b) simp son's rule to approximate the integral? can you please explain? thank you!!

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{0}^{2} \frac{ x }{ 1+x^2 } dx \]

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2its finding an approximation to the area under the curve ...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes:) how can i set it up? I'm a bit confused with the process :o

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2instead of left or right values, you are grabbing the value at the middle of the interval

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ooh okay! yes:) what do we do to start off?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2im not sure how easy it would be to construct the rule .. your material should have it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay! then, could you please show me how id go about solving this integral?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2the hardest part is constructing the rule .. since i dont recall the formula for it off hand. do you have the formula for it?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2dw:1443474213664:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes! it is this for midpoint rule integral of a to b f(x) dx is approximately M_n = delta x [f(x1)+f(x2)+….+f(xn)] where delta x = ba / n and xi=1/2(xi1 + xi) = midpoint of [xi1, xi]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@amistre64 @IrishBoy123 ?

zpupster
 one year ago
Best ResponseYou've already chosen the best response.0i never heard of this but i watched this video and I understand it but it is a lot of work https://www.youtube.com/watch?v=fKtSR0_xf5g

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2powers fluctuating over here ... so my connection isnt stable

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2f (a + ((i_n)dx+(i_(n+1)dx)/2 ) f (a + ((i_n)+(i_(n+1)) dx/2 ) , for i from a to n1

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2\[\sum_{i=0}^{n1}f(\color{red}{a+\frac12\left( i\frac{ba}{n}+(i+1)\frac{ba}{n}\right)})\] \[\sum_{i=0}^{n1}f(\color{red}{a+\frac{ba}{2n}\left( 2i+1\right)})\] does that seem plausible?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2a=0, b=2 sooo \[\sum_{i=0}^{9}f(\color{red}{\frac{2i+1}{10}})\frac1{10}\]

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2x= 1/10 3/10 5/10 7/10 9/10 11/10 13/10 15/10 17/10 19/10

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2determine f(x) for each value of x ....

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2simpsons rule is using a parabolic shape to define the points of reference with.
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