Homework help asap please: f(x) = 3/x-4 g(x) =(3/x)+4 Find f(g(x)) and g(f(x)), then find the f^-1(x) and check using f(f^-1(x) =x and f^-1(f(x) =x

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Homework help asap please: f(x) = 3/x-4 g(x) =(3/x)+4 Find f(g(x)) and g(f(x)), then find the f^-1(x) and check using f(f^-1(x) =x and f^-1(f(x) =x

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Other answers:

Are you in Connexus?
no, I not. I'm simply stumped on this question.
I have tried solving this one many times, but its not working out.
I don't think I could be of much help here...I'm practically useless here :/
try iambatman c:
@iambatman , can you please help me with my homework question
f(g(x)) means you take the function g(x) and plug it into the x of the function f(x), so for example if I have \[f(x) = 3x^2+5\] and \[g(x) = 9x+2\] and we have to find f(g(x)) we take g(x) and plug it into the x of f(x) so we get \[f(g(x)) = 3(9x+2)^2+5\] and then you simplify etc..
And the \[f^{-1}(x)\] implies inverse, to do that we can follow these steps: Replace f(x) with y Switch x's and y's, so put x where y is and y where x is (originally). Solve for y Replace y with f^-1(x)
the lasttime I tried the problem, I had f(g(x) = 3/((3/x) +4) -4

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