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anonymous

  • one year ago

fan and medal this is the equation f(x)=x^2-8x-84 the vertex (4,-100) axis of symmetery is 4 but how do I find three extra points to plot on the graph

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  1. jdoe0001
    • one year ago
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    well, is a quadratic, so it'd look like a bowl so just pick one point to the left of the vertex another point to the right of the vertex and then you have the vertex, and draw the bowl so you really just need two, but if you need a third one, sure :)

  2. anonymous
    • one year ago
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    I would do that but I need to show how I found tit

  3. anonymous
    • one year ago
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    *it

  4. anonymous
    • one year ago
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    @pooja195 can you help please

  5. jdoe0001
    • one year ago
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    how you found it? well, you have the equation :), just pick any random "x" value and get a "y" and that's a point :)

  6. pooja195
    • one year ago
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    You're already getting help

  7. triciaal
    • one year ago
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    if you factor the quadratic then you will have the 2 x-values for when y = 0

  8. anonymous
    • one year ago
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    so would the other three points be (2,-112) and (1,-91)

  9. anonymous
    • one year ago
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    @vera_ewing do you get this

  10. triciaal
    • one year ago
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    |dw:1443588133366:dw|

  11. triciaal
    • one year ago
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    |dw:1443588198587:dw||dw:1443588313192:dw|

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