anonymous
  • anonymous
fan and medal this is the equation f(x)=x^2-8x-84 the vertex (4,-100) axis of symmetery is 4 but how do I find three extra points to plot on the graph
Mathematics
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anonymous
  • anonymous
fan and medal this is the equation f(x)=x^2-8x-84 the vertex (4,-100) axis of symmetery is 4 but how do I find three extra points to plot on the graph
Mathematics
katieb
  • katieb
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jdoe0001
  • jdoe0001
well, is a quadratic, so it'd look like a bowl so just pick one point to the left of the vertex another point to the right of the vertex and then you have the vertex, and draw the bowl so you really just need two, but if you need a third one, sure :)
anonymous
  • anonymous
I would do that but I need to show how I found tit
anonymous
  • anonymous
*it

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anonymous
  • anonymous
@pooja195 can you help please
jdoe0001
  • jdoe0001
how you found it? well, you have the equation :), just pick any random "x" value and get a "y" and that's a point :)
pooja195
  • pooja195
You're already getting help
triciaal
  • triciaal
if you factor the quadratic then you will have the 2 x-values for when y = 0
anonymous
  • anonymous
so would the other three points be (2,-112) and (1,-91)
anonymous
  • anonymous
@vera_ewing do you get this
triciaal
  • triciaal
|dw:1443588133366:dw|
triciaal
  • triciaal
|dw:1443588198587:dw||dw:1443588313192:dw|

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